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Liula [17]
3 years ago
9

PLEASSSSSE HELPPPPPP This is my third post of this! I really need help

Mathematics
1 answer:
Nesterboy [21]3 years ago
6 0
Answer: x=25

solution:

we know that
The triangle external angle theorem states that: An exterior angle of a triangle is equal to the sum of the opposite interior angles

In this problem:
m∠9=m∠7+m∠8

substitute the given values:
(6x-20)°=30°+4x°

now solve for x:
6x-4x=30+20
2x=50
x=25 which is the final answer:)
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You invest $40,000 in two funds paying 4% and 52% simple interest. The total annual interest is $2080. How much do you invest in
natali 33 [55]

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Answer:

  • 4% fund: $39,000
  • 52% fund: $1000

Step-by-step explanation:

Let x represent the amount invested at 52%. Then (40000-x) is the amount invested at 4%. The total annual interest is ...

  0.52x +0.04(40000-x) = 2080

  0.48x = 480 . . . . . . . . . subtract 1600, simplify

  x = 1000 . . . . . . . . . divide by 0.48

Then the amounts invested in each fund are ...

  4% fund: $39,000

  52% fund: $1000

6 0
3 years ago
Can someone help answer the first two?
Murljashka [212]

Answer:

below given!

Step-by-step explanation:

1) mean = (7.4 + 5.8 + 7.3 + 7 + 8.9 + 9.4 + 8.3 + 9.3 + 6.9 + 7.5 + 9 + 5.8 + 5.5 + 8.6 + 9.3 +3.8) / 16

mean = 7.47

5 0
3 years ago
2/3 (x-7) = -2 please please help!!
Maslowich

Answer:

x = 4.

Step-by-step explanation:

Distribute, isolate and solve.

3 0
3 years ago
The results of a survey indicate that the true proportion of households who want a park in their neighborhood is likely in the i
GrogVix [38]

Answer:

0.66

Step-by-step explanation:

What are you giving there is a confidence interval. You can obtain a confidence interval based on a sample you got. The length of the confidence interval is determined on how much confidence do you want for your interval (the probability of the real value being inseide the interval) and how big is the sample: the bigger the sample, the smaller the length of the confidence interval. Independently of the sample length, all intervals are centered on the average value you got for the sample, and that is your estimate. In this case, the center of the interval is 0.52+0.8/2 = 0.66.

4 0
3 years ago
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