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3 years ago

Find the missing side, please

Mathematics

1 answer:

AVprozaik [17]3 years ago

4 0

Answer:

a. √442, b. √540, c. 8

Step-by-step explanation:

remember that a^2 + b^2 = c^2

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If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid

Artist 52 [7]

Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.

$\bf \textit{volume of a rectangular prism}\\\\
V=lwh\quad 
\begin{cases}
l = length\\
w=width\\
h=height\\
-----\\
w=l=x
\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\
-------------------------------\\\\
\textit{surface area}\\\\
S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h
\\\\\\
\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\
-------------------------------\\\\
V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3$

so.. that'd be the V(x) for such box, now, where is the maximum point at?

$\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2
\\\\\\
\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100
\\\\\\
x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}$

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.

so, the volume will then be at $\bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3$

6 0

3 years ago

HELPPPPPP MEEEE THANKSS

stepan [7]

3,500 it is that your welcome I have the same problem right now

6 0

3 years ago

Read 2 more answers

Marla bought 12 books at a garage sale. Some of them were hardback and the rest were paperback. She paid $0.50 for each paperbac

olga nikolaevna [1]

Answer: The number of books bought were 9 paperbacks and 3 hardbacks

Step-by-step explanation: We shall start by assigning letters to the unknown variables, hence let the hardback be called h, while the paperback shall be called p.

If Marla bought 12 books at the garage sale, that means she bought

h + p = 12 ------(1)

Then she paid 0.5 dollars for paperback and 0.75 dollars for hardback and the total spent was 6.75 dollars for all of them, then we can express these as follows;

0.5p + 0.75h = 6.75 ------(2)

We now have a pair of simultaneous equations which are

h + p = 12 ------(1)

0.5p + 0.75h = 6.75 ------(2)

From equation (1), make h the subject of the equation,

h = 12- p

Substitute for h into equation (2)

0.5p + 0.75(12 - p) = 6.75

0.5p + 9 - 0.75p = 6.75

0.5p - 0.75p = 6.75 - 9

-0.25p = -2.25

Divide both sides of the equation by -0.25

p = 9

Now, substitute for p into equation (1)

h + p = 12

h + 9 = 12

Subtract 9 from both sides of the equation

h = 3

Therefore Marla bought 9 paperbacks and 3 hardbacks

6 0

3 years ago

Read 2 more answers

Kristian buys a meal for $8.40 calculate the fraction of the $72 after buying the computer game which costed $32.40 and the meal

brilliants [131]

Answer:

After buying the meal and the computer game, Kristian has 43.33% of his money left.

Step-by-step explanation:

Given that Kristian buys a meal for $ 8.40, to calculate the fraction of the $ 72 after buying the computer game which cost $ 32.40 and the meal, the following calculation must be performed:

72 = 100

8.40 + 32.40 = X

72 = 100

40.80 = X

40.80 x 100/72 = X

4,080 / 72 = X

56.66 = X

100 - 56.66 = 43,333

Therefore, after buying the meal and the computer game, Kristian has 43.33% of his money left.

7 0

3 years ago

Yolanda spends 8/23 hours per month playing soccer. Approximately how many hours does she play soccer in a year

Novosadov [1.4K]

Given:
8 2/3 hours per month
12 months in a year.

Number of hours she play soccer in a year.

8 2/3 must be converted to improper fraction.

((8*3)+2)/3 = 26/3

26/3 * 12 = (26 * 12)/3 = 312/3 = 104

Yolanda spends 104 hours in a year playing soccer.

5 0

3 years ago

Read 2 more answers