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RoseWind [281]
3 years ago
11

Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing t

he first one, selects another marble at random. What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.
Mathematics
1 answer:
nekit [7.7K]3 years ago
6 0
Answer=25%

14 red marbles
12 yellow marbles
26 total marbles

To solve this, we need to first find out the probability of the individual events...

The odds of selecting a red marble is 14 out of 26 total marbles: 14/26

The odds of selecting a yellow marble after the first marble was NOT replaced is 12 out of 25. (25 since the first marble wasn't replaced: 26-1=25) 12/25

Now lets multiple both probabilities together to solve for the chance of both happening consecutively....

14/26*12/25= 168/650=84/325

84/325=<span>0.25846153846= 25%</span>
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Step-by-step explanation:

Given

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Answer:

the least integer for n is 2

Step-by-step explanation:

We are given;

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centered at x=0

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(n!/(n + 1)!) × 0.2^(n + 1) < 0.01

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Answer:

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Answer:

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The correct answer is the last choice.

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