Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing t
he first one, selects another marble at random. What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.
To solve this, we need to first find out the probability of the individual events...
The odds of selecting a red marble is 14 out of 26 total marbles: 14/26
The odds of selecting a yellow marble after the first marble was NOT replaced is 12 out of 25. (25 since the first marble wasn't replaced: 26-1=25) 12/25
Now lets multiple both probabilities together to solve for the chance of both happening consecutively....
Make a box putt the 70% at the top on the ouside then sub 100%-70% the box should have 4 squares so then on the bottom of the box on the outside. it should be 30% then in the top left corner put 28 and under it 46 then do 46/28 × 70% over 1 see if that helps
