Step-by-step explanation:
<h3>1. x² + 4 = (x+2)² </h3>
<h3> : x² + 4 = x² + 4 (Yes)</h3>
<h3>2. (2x+6)²= 4(x+3)²</h3>
<h3> : 4x²+36 = 4x² + 36 ( Yes)</h3>
<h3>3. (x-3)(x-3)= (x-9)² (NO)</h3>
<h3>beacause , True statement is</h3><h3> (x+3)(x-3)= (x-9)²</h3>
<h3>4. x²-10x+25 = (x-5)(x+5) (No)</h3>
<h3> : x²-2x+y² = (a-b)(a+b) </h3>
<h3>Therefore, its not true statement!</h3>
Answer:
I think (D)
Step-by-step explanation:
I'm taking the liberty of editing your function <span>v = e5xey: It should be
</span>
<span>v = e^5x^ey, with " ^ " indicating exponentiation.
</span>
Did you mean e^(5x) or (e^5)x? I'll assume it's e^(5x).
The partial of v = e^(5x)e^y with respect to x is e^(5x)(5)*e^y, or 25x*e^y.
The partial of v = e^(5x)e^y with respect to y is e^(5x)e^y.
Answer:
Explanation:
Translate every verbal statement into an algebraic statement,
<u>1. Keith has $500 in a savings account at the beginning of the summer.</u>
<u>2. He wants to have at least $200 in the account by the end of summer. </u>
<u />
<u>3. He withdraws $25 a week for his cell phone bill.</u>
<u />
- Call w the number of weeks
<u>4. Write an inequality that represents Keith's situation.</u>
- Create your model: Final amount = Initial amount - withdrawals ≥ 500
With that inequality you can calculate how many week will pass before his account has less than the amount he wants to have in the account by the end of summer:
That represents that he can afford spending $ 25 a week during 12 weeks to have at least $ 200 in the account.
