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Vladimir [108]
3 years ago
8

You can pay $10 for 2 movie tickets assuming the same rate , how much would you pay for 5 movie tickets ?

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

If we assume every 2 movie tickets is $10 then every one ticket would be $5. Assuming this to be true then 5 tickets is $25.

StepByStep Explanation:

movie tickets = t

2t=10

t=5

5t=?

5(5)=?

25=?

?=25


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Answer:

d=hf+5

Step-by-step explanation:

Step 1: Factor out variable d.

d(f+5)=h

Step 2: Divide both sides by f+5.

d(f+5)f+5=hf+5

d=hf+5

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you had eight hours until you have to be on set if you will spend 3/4 of an hour driving to the TV station how much time does th
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7 hours and 15 minutes

Step-by-step explanation:

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The perimeter of a triangle is 27 inches. The second side is 3 inches longer than the first side and the third side is twice as
Angelina_Jolie [31]
Divided 27 inches by the length of each side.
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If u(x) =-2x^2 and v(x)=1 over x what is the range of (uov) (x)
Radda [10]

u(x) = -2x², v(x)= 1/x

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6 0
3 years ago
How do I complete these questions a bit confused . (extra credit work )​
otez555 [7]

Answer:

(1)

a = \frac{3\sqrt 3}{2}

b = \frac{3}{2}

(2)

a = \sqrt 6

b = \sqrt 2

Step-by-step explanation:

Solving (1):

Considering

\theta = 60^o

We have:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60^o) = \frac{a}{3}

Solve for a

a = 3 * \sin(60^o)

\sin(60^o) = \frac{\sqrt 3}{2}

So:

a = 3 * \frac{\sqrt 3}{2}

a = \frac{3\sqrt 3}{2}

To solve for b, we make use of Pythagoras theorem

3^2 = a^2 + b^2

This gives

3^2 = (\frac{3\sqrt 3}{2})^2 + b^2

9 = \frac{9*3}{4} + b^2

9 = \frac{27}{4} + b^2

Collect like terms

b^2 = 9 - \frac{27}{4}

Take LCM and solve

b^2 = \frac{36 - 27}{4}

b^2 = \frac{9}{4}

Take square roots

b = \frac{3}{2}

Solving (2):

Considering

\theta = 60^o

We have:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60^o) = \frac{a}{2\sqrt 2}

Solve for a

a = 2\sqrt 2 * \sin(60^o)

\sin(60^o) = \frac{\sqrt 3}{2}

So:

a = 2\sqrt 2 * \frac{\sqrt 3}{2}

a = \sqrt 2 * \sqrt 3

a = \sqrt 6

To solve for b, we make use of Pythagoras theorem

(2\sqrt 2)^2 = a^2 + b^2

This gives

(2\sqrt 2)^2 = (\sqrt 6)^2 + b^2

8 = 6 + b^2

Collect like terms

b^2 = 8 - 6

b^2 = 2

Take square roots

b = \sqrt 2

3 0
3 years ago
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