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Blizzard [7]
3 years ago
6

Evaluate the integral: integral of t sinh mt dt

Mathematics
1 answer:
yanalaym [24]3 years ago
5 0
Integrate by parts 

<span>f = t, df = dt, </span>
<span>dg = sinh(mt)dt </span>
<span>g = cosh(mt)/m </span>

<span>put them together </span>

<span>tcosh(mt)/m - /m * ∫cosh(mt)dt </span>

<span>u = mt, du = mdt </span>
<span>tcosh(mt)/m - /m^2 * ∫cosh(u)dt </span>
<span>integral of cosh(u) = sinh(u) </span>

<span>tcosh(mt)/m - sinh(u)/m^2 + c1 </span>

<span>substitute back in the u (mt) </span>
<span>tcosh(mt)/m - sinh(mt)/m^2 + c1 </span>

<span>You can simplify this </span>

<span>((mt*cosh(mt)-sinh(mt)))/m^2</span>
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