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julia-pushkina [17]
3 years ago
5

What is a Quadratic Function?

Mathematics
2 answers:
Anestetic [448]3 years ago
8 0
One that has its highest degree = 2
Examples

x^2

x^2 - 1

x^2 + 5x - 6
meriva3 years ago
3 0
X=(-b±√(b^2-4ac))/2a
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Which statement best explains why this expression is equal to 9.4? A)Any expression multiplied by 0 equals 0. B)Any number divid
tigry1 [53]

Answer: A.

Step-by-step explanation:

yeet

5 0
3 years ago
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(4+7 +5+5+2) +[14 5/8+ 14 3/4 +14 7/8+15 + 15 1/8]=​
Reptile [31]

Answer:

97 and 1/8

Step-by-step explanation:

(4 + 7 + 5 + 5 + 2) + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)

23 + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)

23 + 74 1/8

97 and 1/8

7 0
2 years ago
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Please help me Solve -2a -5>3
worty [1.4K]

Answer:

a < -4

Step-by-step explanation:

Step 1: Write out inequality

-2a - 5 > 3

Step 2: Add 5 to both sides

-2a > 8

Step 3: Divide both sides by -2

a < -4

Here, we can see that any value of <em>a </em>less than -4 works. So <em>a</em> could be -124 or -5, or even -1271293587923857 and it would work.

4 0
3 years ago
X+(x+2)+(x+4)+(x+6)=4x+12=212
Mrac [35]

(x+(x+2)+(x+4)+(x+6))=4x+12=212

x+x+x+x(2+4+6)=4x+12=212

4x (2+4+6)=4x+12=212

4x(6+6)=4x+12=212

12+4x=4x+12=212

<u>-12            -12   -12</u>

4x=4x=200

<u>/4  /4  /4</u>

<u>x=x=50</u>

<u>x=50</u>

4 0
3 years ago
Given that 2y^3+by-cy+d,where b,c and d are constants,leaves a remainder R when divided by (y+1) , (y-2) and (2y-1). Find the va
Eddi Din [679]

The polynomial remainder theorem says that a polynomial <em>p(x)</em> leaves a remainder of <em>p(k)</em> when it's divided by <em>x</em> - <em>k</em>.

We're given that dividing <em>p(y)</em> = 2<em>y</em>³ + <em>by</em>² - <em>cy</em> + <em>d</em> leaves the same remainder <em>R</em> after dividing it by <em>y</em> + 1, <em>y</em> - 2, and 2<em>y</em> - 1. So we have

<em>p</em>(-1) = 2(-1)³ + <em>b</em>(-1)² - <em>c</em>(-1) + <em>d</em> = <em>R</em>

==>  <em>R</em> = -2 + <em>b</em> + <em>c</em> + <em>d</em>

<em>p</em>(2) = 2(2)³ + <em>b</em>(2)² - <em>c</em>(2) + <em>d</em> = <em>R</em>

==>  <em>R</em> = 16 + 4<em>b</em> - 2<em>c</em> + <em>d</em>

<em>p</em>(1/2) = 2(1/2)³ + <em>b</em>(1/2)² - <em>c</em>(1/2) + <em>d</em> = <em>R</em>

==>  <em>R</em> = 1/4 + <em>b</em>/4 - <em>c</em>/2 + <em>d</em>

<em />

We're also given that <em>y</em> + 2 is a factor, which means dividing <em>p(y)</em> by it leaves no remainder, and so

<em>p</em>(-2) = 2(-2)³ + <em>b</em>(-2)² - <em>c</em>(-2) + <em>d</em> = 0

==>  0 = -16 + 4<em>b</em> + 2<em>c</em> + <em>d</em>

<em />

Solve the system of equations in boldface. You can eliminate <em>d</em> from the first 3 to first solve for <em>b</em> and <em>c</em>, then solve for <em>d</em> :

(-2 + <em>b</em> + <em>c</em> + <em>d</em>) - (16 + 4<em>b</em> - 2<em>c</em> + <em>d</em>) = <em>R</em> - <em>R</em>

-18 - 3<em>b</em> + 3<em>c</em> = 0

<em>b</em> - <em>c</em> = -6

(-2 + <em>b</em> + <em>c</em> + <em>d</em>) - (1/4 + <em>b</em>/4 - <em>c</em>/2 + <em>d</em>) = <em>R</em> - <em>R</em>

-9/4 + 3<em>b</em>/4 + 3<em>c</em>/2 = 0

<em>b</em> + 2<em>c</em> = 3

(<em>b</em> - <em>c</em>) - (<em>b</em> + 2<em>c</em>) = -6 - 3

-3<em>c</em> = -9

<em>c</em> = 3

<em>b</em> - 3 = -6

<em>b</em> = -3

-16 + 4(-3) + 2(3) + <em>d</em> = 0

<em>d</em> = 22

7 0
3 years ago
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