<h3>
Therefore the area of remaining board =13.76 square feet</h3>
Step-by-step explanation:
Given , The length of side of the square is 8 feet.
Since a circle is inscribed in the square. Then the diameter of the circle is equal to the length of side of the square .
Therefore the diameter of the circle is = 8 feet.
Radius of the circle is(r) = 
feet = 4 feet
The area of the circle is= 3.14 r²
= 3.14 × 4² square feet
= 50.24 square feet
The area of the square is = side × side
= 8×6 square feet
=64 square feet
Therefore the area of remaining board = (64- 50.24)square feet
=13.76 square feet
Answer:
Only about 1/3 of the pencils have erasers.
The length of arc AB is 9.12 mm:
We first calculate for the radius r of the circle using the equation
r = c/(2 sin[theta/2])
where c is the length of chord AB that is given as 9 millimeters
angle given is 32 degrees
To convert theta 32 degrees into radians:
32 degrees * (pi/180) = 32 degrees * (3.14/180) = 0.5583 radians
We now substitute the values into the equation to find the radius r:
r = 9/(2 sin[0.5583/2])
r = 16.33 mm
.
We can finally solve for the length s of arc:
s = r theta = 16.33 * 0.5583 = 9.12 mm
3y - x = 6 (Note: the formula for slope-intercept form is y = mx + b)
3y = x + 6 (moving the x over to separate both variables)
y = x/3 + 6/3 (after dividing both sides by 3)
y = x/3 + 2 (simplify)
Hope this helps! :)
