Draw DH perpendicular to AE.
By the Side-Angle-Side postulate ΔABE = ΔBEF.
this is the enitre answer: https://web2.0calc.com/questions/in-square-abcd-e-is-the-midpoint-of-line-bc-and-f-is-the-midpoint-o...
Answer:
4) 16√3 in²
5) 63 cm²
Step-by-step explanation:
The formula to use in these cases is ...
A = (1/2)ab·sin(θ)
where a, b are the side lengths and θ is the angle between them.
It helps to know the trig functions of the "special" angles used here.
sin(120°) = sin(60°) = (√3)/2
cos(60°) = 1/2
sin(135°) = cos(45°) = (√2)/2
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4) The external angle at the base is the supplement of 120°, so is 60°. Then the length of the missing segment between the end of the base and the right angle at h is ...
x = (8 in)cos(60°) = (8 in)(1/2) = 4 in
So, the bottom edge of the triangle is 12 in - 4 in = 8 in.
The area is ...
A = (1/2)(8 in)(8 in)sin(120°) = (1/2)64(√3)/2 in² = 16√3 in²
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5) As in the previous problem, the difference between the given horizontal dimension and the base of the triangle is ...
x = (18 cm)cos(180°-135°) = 18(√2)/2 cm = 9√2 cm
Then the base of the triangle is ...
16√2 cm -9√2 cm = 7√2 cm
The area is then ...
A = (1/2)(18 cm)(7√2 cm)(√2)/2 = 63 cm²
-30a^5b+12a^4b^3+16a^3b^2-4a^2b^4-2ab^3
THE ANSWER IS C !! DONT CHOSE NOTHING ELSE OR YOULL GET IT WRONG
Answer:
Step-by-step explanation:
1) Number of white chocolate bars = x
Number of dark chocolate bars = y
Total bars = 15
x + y = 15 --------------(I)
Total cost = Php. 340
20x + 25y = 340 ----------------(II)
2) We can use elimination method to solve this equations.
Multiply equation (I) by (-20) and then add the equations.
(I)* (-20) -20x -20y = - 300
(II) <u>20x + 25y = 340 </u> {Now add and x will be eliminated}
5y = 40
y = 40/5
y = 8
Substitute y = 8 in equation (I)
x + 8 = 15
x = 15 - 8
x = 7
3) Number of dark chocolate bars = 8
