A rectangle with sides 15 and w has perimeter

We want this quantity to be at most 50, so it must be less than or equal to 50:

For the record, this implies that

So, the width can be at most 10.
Answer: PQR=32
Step-by-step explanation:
RQS+PQR=PQS
(4x+4)+(3x-1)=80
7x+3=80
7x=77
x=11
PQR=(3x-1)=> (3(11)-1) => 33-1=32
look at the whole numbers and not the tenths and hundreds and stuff.
<span>1, 2, 3.25, and then the fraction </span>