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3 years ago

9

58 1/3 divided by 6 2/3 work is needed!!

1 answer:

Slav-nsk [51]3 years ago

4 0

I decided to write out the answer in paint, you can see it as an attachment.

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What is three million, seven hundred twenty four in number form

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The answer would be 3,000,724.

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A basketball player has made 60 out of 125 attempts. How many shots is he likely to make in 500 attempts?

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si qeustonius el uniqus

Step-by-step explanation:

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3 years ago

suppose a study estimated that 78% of the residents of a town (with an error range plus/minus12 percentage points at 95% confide

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Consider the function f(x)=|x+3|−5 and its graph, which follows.

sergiy2304 [10]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$f\left(x\right)=\left|x+3\right|-5$

Obtain the function g(x)

$g(x)=-\frac{1}{5} f(x)$

substitute

$g(x)=-\frac{1}{5} [\left|x+3\right|-5]$

$g(x)=-\frac{1}{5}\left|x+3\right|+1$

using a graphing tool

The graph in the attached figure

The vertex is the point (-3,1)

The x-intercepts are the points (-8,0) and (2,0)

The y-intercept is the point (0,0.4)

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3 years ago

A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.

Katen [24]

Answer:

Part A:- $x +11 ft$ Part B:- $(4x+54)ft$ part C:- $x= 2ft$

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

Given that,

length and breadth of Trapdoor are $(x+ \frac{1}{2} ) by 2x$ ft.

The Outside length of Rectangle is $(x+16 )$ ft.

Part A:- Total area (in square feet) of the stage can be represented by

$x^{2} + 27x+ 176$ . Write an expression for the width of stage.

So, Area of rectangle = $length \times breadth$

$x^{2} + 27x+ 176 = (x+16) \times breadth$

$Breadth = \frac{x^{2} + 27x+ 176}{x+16}$

$Breadth = x+11$ ft. ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here, Perimeter of Rectangle = $2(L+B)$

= $2(x+16 + x +11)$

= $(4x + 54) ft$

Part C:- The area of trapdoor is $10 ft^{2}$ . Find the value of x.

So, Area of trapdoor = $10 ft^{2}$

$(x +\frac{1}{2}) \times 2x =10 ft^{2}$

$2x^{2} +x - 10 = 0$

$x = \frac{-1-9}{4}$ , $\frac{-1+9}{4}$

$x = \frac{-5}{2}$ , $2$

Hence value of x is $2 ft$ (Neglecting the negative value because

length cannot be negative).

Part D:- The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So, Length of trapdoor is $(2+\frac{1}{2} ) = \frac{5}{2} ft$

breadth of trapdoor is $2\times 2 = 4ft$

Now, outside length of Rectangle is = $18ft$

And outside breadth of rectangle is = $13ft$

Here, Area of trapdoor = $\frac{5}{2} \times 4 = 10ft^{2}$ ...................(2)

Area of rectangle = $18 \times 13= 234 ft^{2}$ ....................(3)

Thus comparing Equation (1) & (2) we found that

Area of rectangular stage is 20 times greater than the area of trapdoor.

7 0

3 years ago