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3 years ago

Companies with strong safety cultures usually have lower _____.

Mathematics

2 answers:

motikmotik3 years ago

6 0

<span>Companies with strong safety cultures usually have lower turnover.</span>

puteri [66]3 years ago

3 0

Turnover is your answer. I hope this helped!

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Initially a tank contains 10 liters of pure water. Brine of unknown (but constant) concentration of salt is flowing in at 1 lite

zhenek [66]

Answer:

Therefore the concentration of salt in the incoming brine is 1.73 g/L.

Step-by-step explanation:

Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.

Let the concentration of salt be a gram/L

Let the amount salt in the tank at any time t be Q(t).

$\frac{dQ}{dt} =\textrm {incoming rate - outgoing rate}$

Incoming rate = (a g/L)×(1 L/min)

=a g/min

The concentration of salt in the tank at any time t is = $\frac{Q(t)}{10}$ g/L

Outgoing rate = $(\frac{Q(t)}{10} g/L)(1 L/ min)$ $\frac{Q(t)}{10} g/min$

$\frac{dQ}{dt} = a- \frac{Q(t)}{10}$

$\Rightarrow \frac{dQ}{10a-Q(t)} =\frac{1}{10} dt$

Integrating both sides

$\Rightarrow \int \frac{dQ}{10a-Q(t)} =\int\frac{1}{10} dt$

$\Rightarrow -log|10a-Q(t)|=\frac{1}{10} t +c$ [ where c arbitrary constant]

Initial condition when t= 20 , Q(t)= 15 gram

$\Rightarrow -log|10a-15|=\frac{1}{10}\times 20 +c$

$\Rightarrow -log|10a-15|-2=c$

Therefore ,

$-log|10a-Q(t)|=\frac{1}{10} t -log|10a-15|-2$ .......(1)

In the starting time t=0 and Q(t)=0

Putting t=0 and Q(t)=0 in equation (1) we get

$- log|10a|= -log|10a-15| -2$

$\Rightarrow- log|10a|+log|10a-15|= -2$

$\Rightarrow log|\frac{10a-15}{10a}|= -2$

$\Rightarrow |\frac{10a-15}{10a}|=e ^{-2}$

$\Rightarrow 1-\frac{15}{10a} =e^{-2}$

$\Rightarrow \frac{15}{10a} =1-e^{-2}$

$\Rightarrow \frac{3}{2a} =1-e^{-2}$

$\Rightarrow2a= \frac{3}{1-e^{-2}}$

$\Rightarrow a = 1.73$

Therefore the concentration of salt in the incoming brine is 1.73 g/L

8 0

3 years ago

Find the distance between the points (1, 5) and (1, -4).

Ganezh [65]

Answer:

Step-by-step explanation:

$\tt distance=\sqrt{(1-1)^2+(-4-5)^2}=\sqrt{0^2+9^{2}}=\sqrt{9^2} =9$

6 0

3 years ago

Read 2 more answers

a bank loaned out $18,000 part of it at the rate of 7% per year and the rest at 15% per year. if the interest received in one ye

alexdok [17]

I think it’s 2,000 but again I could be wrong I need like the options

8 0

2 years ago

John and Gary share a workload. At a certain point, John worked 2 more hours than Gary. The next day, John has worked 4 of Gary’

il63 [147K]

If these both men were working at normal hours, and then, (John) worked "2 more hours" than Gary has, this would just mean that he has worked more.

x+2= x+2.

Now if John has worked the double amount, 4 more times than Gary's usual hours, this would mean something quite different.

Then the expression would look like, (x+2×4x)

We don't know how many hours are the "usual hours", this is what "x" would then represent.

John has then worked (4×2+x) more hours than Gary.

Your answer: (4×2+x)

4 0

3 years ago

Write an equivalent

erma4kov [3.2K]

Answer:

By substituting the value of the variable and simplifying it with the equation you get 158.

3 0

3 years ago