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ValentinkaMS [17]
3 years ago
5

Kareem wants to write an equation for the data in the table below.

Mathematics
2 answers:
Anton [14]3 years ago
6 0
The answer is:

y = ab^x


the proper answer is:
( y = 2^x)
agasfer [191]3 years ago
6 0

We are given with the table of x  and y values

We use the given y values to find the required equation

When the first difference between the y values are same then it is linear.

When the common ratio between y values are same then it is exponential.

When the second difference of y values are same then it is quadratic.

Lets find the difference between y values

\frac{1}{4} - \frac{1}{8} = \frac{1}{8}

\frac{1}{2} - \frac{1}{4} = \frac{1}{4}

1 - \frac{1}{2} = \frac{1}{2}

The difference is not same . so we cannot choose y= mx+b

Now we find the common difference between y values

\frac{\frac{1}{4}}{\frac{1}{8}} = 2

\frac{\frac{1}{2}}{\frac{1}{4}} = 2

\frac{1}{\frac{1}{2}} = 2

The common ratio is 2. So its exponential.

The required equation y=ab^x

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