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3 years ago

I need help with these plzz

Mathematics

2 answers:

Maurinko [17]3 years ago

8 0

I’m not sure . I don’t have a big brain to answer that

dimaraw [331]3 years ago

6 0

Uhh my brains hurts looking at that

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In Zoe's class, 4/5 of the students have pets. Of the students who have pets, 1/8 have rodents. What fraction of the students in

scoundrel [369]

Yoir answer would be 27 out of 40.

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3 years ago

In ABC, if m find the measure of each angle.

monitta

Answer:

Let the angles have measures 2x,3x,4x

Then 2x+3x+4x = 180

and the rest is easy

Step-by-step explanation:

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2 years ago

A pilot flies on a bearing of 160° for 30 miles. The pilot then executes a quick turn and flies another 15 miles at a bearing of

vivado [14]

Answer: 34.65 miles at an angle of 325.39°

Step-by-step explanation:

Ok, the initial position is (0,0)

Then she flies 30 miles at an angle of 160°, if we count the angle counterclokwise from the x-axis, the new position will be:

p = (30*cos(120°), 30*sin(120°))

Then she travels another 15 miles at an angle of 205°, the new position is:

p = (30*cos(120°) + 15*cos(205°), 30*sin(120°) + 15*sin(205°))

p = (-28.59 , 19.64)

If she now travles X miles at an angle Y, we must have that the final position is the point (0,0)

this means that:

X*cos(Y) = -(-28.59) = 28.59

X*sin(Y) = -19.64

Now, we can find the quotient between those two equations and use that tan(x) = sin(x)/cos(x)

X*(sin(Y))/(X*cos(Y)) = -19.64/28.59

Tg(Y) = -0.69

Y = ATg(-0.69) = -34.61°

If we use only positive angles, this angle is equivalent to:

360° - 34.61° = 325.39°

now lets find the distance:

Xcos(325.39°) = 28.59

X = 28.59/cos(325.39°) = 34.65 miles.

4 0

3 years ago

Karl is building a rectangular garden bed. The length is 6 feet. She has 20 feet of boards to make the sides. Write and solve an

natali 33 [55]

Answer:

The width of the garden bed must be less than or equal to 4 feet.

$w\leq4$

Explanation:

Given that;

She has 20 feet of boards to make the sides.

The perimeter of the garden bed must not be more than 20 feet

$\begin{gathered} P=2l+2w\leq20 \\ 2l+2w\leq20 \end{gathered}$

Given;

The length is 6 feet;

$l=6$

To get the inequality for the width w, let us substitute the value of the length into the inequality above and simplify;

$\begin{gathered} 2l+2w\leq20 \\ 2(6)+2w\leq20 \\ 12+2w\leq20 \\ 2w\leq20-12 \\ 2w\leq8 \\ \frac{2w}{2}\leq\frac{8}{2} \\ w\leq4 \end{gathered}$

Therefore, the width of the garden bed must be less than or equal to 4 feet.

$w\leq4$

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1 year ago

A bike rental stand at the beach charges $5 to rent a bike then charges $2 every half hour it is rented is someone pay $70 for t

lord [1]

Answer:

Step-by-step explanation:

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3 years ago