Answer:
I'm just guessing so don't judge. 3
Step-by-step explanation:
Answer:
Step-by-step explanation:
Area= length x width
area=6/7, length=3/5, width=?
6/7=3/5 x width
6/7 divided by 3/5= 6/7 x 5/3 (you have to multiply by the recipricol, or flip the fraction.)
6/7 x 5/3=30/21= 1 3/7=width
Answer:
13% chance
Step-by-step explanation:
Area of backyard = length * width
A = 30 ft * 20 ft
A = 600
Area of bathtub = π
A = π *
A = 78.54
Probability of arrow landing in tub can be found by dividing Area of the bathtub by the area of the backyard, and then multiplying by 100 for a percentage
Prob. = 78.54/600
Prob. = 0.13
Prob. = 0.13 * 100
Prob. = 13%
Answer:
x=16
Step-by-step explanation:
....,...................
Answer:
(a)77.4bpm
(b)Mean of Sample 1 = 70.3 beats per minute.
Mean pulse of sample 2 = 70 beats per minute.
(c)
- The mean pulse rate of sample 1 underestimates the population mean.
- The mean pulse rate of sample 2 underestimates the population mean.
Step-by-step explanation:
(a)Population mean pulse.
The pulse of the nine students which represent the population are:
- Perpectual Bempah 64
- Megan Brooks 77
- Jeff Honeycutt 89
- Clarice Jefferson 69
- Crystal Kurtenbach 89
- Janette Lantka 65
- Kevin McCarthy 88
- Tammy Ohm 69
- Kathy Wojdya 87
The population mean pulse is approximately 77.4 beats per minute.
(b)Sample 1: {Janette,Clarice,Megan}
- Janette: 65bpm
- Clarice: 69bpm
- Megan: 77bpm
Mean of Sample 1
Sample 2: {Janette,Clarice,Megan}
- Perpetual: 64bpm
- Clarice: 69bpm
- Megan: 77bpm
Mean of Sample 2
The mean pulse of sample 1 is approximately 70.3 beats per minute.
The mean pulse of sample 2 is approximately 70 beats per minute.
(c)
- The mean pulse rate of sample 1 underestimates the population mean.
- The mean pulse rate of sample 2 underestimates the population mean.