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Naya [18.7K]
3 years ago
6

16. A proportional relationship between the number of pounds of tomatoes (x) and the price in dollars (y) is graphed, and the or

dered pair (6,3) is on the graphed line.
What is the price of 1 pound of potatoes? Show your work, including the proportion you used to determine the price.
Mathematics
1 answer:
kondaur [170]3 years ago
4 0

The relationship being proportional means there is a value of k such that

... y = k·x

We are given the point (6 (pounds), 3 (dollars)), so we can write ...

... 3 dollars = k·6 pounds

Dividing by 6 pounds, we get

... (3/6) dollars/pound = k = $0.50/lb

Now, we can use x=1 pound to find the price (y),

... y = ($0.50/lb)·(1 lb)

... y = $0.50 . . . . the price of 1 pound of tomatoes.

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A recipe calls for 2 teaspoons of vanilla and 3/4 cup of sugar. Compute the unit rate for vanilla to sugar. Show your work.
BabaBlast [244]
For every 1 vanilla 4 are sugar???????? Im guessing
4 0
3 years ago
Please show the steps I need this right now I’m taking a test8(x−4)<7x−3
Olegator [25]

Answer:

x < 29

Step-by-step explanation:

8(x−4)<7x−3; distribute 8 in the parenthesis

8x - 32 < 7x - 3; subtract 7x from both sides

x - 32 < -3; add 32 to both sides

x < 29

5 0
3 years ago
The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

8 0
3 years ago
Let x denote the lifetime of a mcchine component with an exponential distribution. The mean time for the component failure is 25
aliina [53]

Answer:

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The mean time for the component failure is 2500 hours.

This means that m = \frac{2500}, \mu = \frac{1}{2500} = 0.0004

What is the probability that the lifetime exceeds the mean time by more than 1 standard deviations?

The standard deviation of the exponential distribution is the same as the mean, so this is P(X > 5000).

P(X > x) = e^{-0.0004*5000} = 0.1353

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

4 0
3 years ago
Xan and Katie are twins. Xan weighs 66 6 6 pounds 99 9 9 ounces, and Katie weighs 88 8 8 pounds 11 1 1 ounce. What is the differ
gtnhenbr [62]

Answer:

264 ounces

Step-by-step explanation:

#Convert Xan weight into ounces:

1lb= 16 \ oz\\\\66\ lb=66\times 16=1056 \ oz\\\\\therefore Xan's=1056 \ oz+ 99 \ oz=1155 \ oz

Convert Katie's 88 pounds 11 ounce to ounces:

1lb= 16 \ oz\\\\88\ lb=88\times 16=1056 \ oz\\\\\therefore Katie's=1408 \ oz+ 11 \ oz=1419\ oz

The difference is calculated by subtracting Xan's from Katie's:

=1419 \ oz-1155 \ oz\\\\=264\ oz

Hence, the difference between the weights is 264 ounces

7 0
3 years ago
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