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Alchen [17]
3 years ago
11

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e.

inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________
Mathematics
1 answer:
zaharov [31]3 years ago
3 0

Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:_Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:______________QuQuestion

Show that for a square Question Question

Show that for a square symmetric matrix M, Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________tric mQuestion

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________atrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________estion

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:______________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:__________________

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Aleksandr [31]

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2.5

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What is 24/400 into decimals
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Tommy's wife wants to fence in her circular garden. How many feet of fencing will she need if the diameter of the garden is 16 f
pashok25 [27]

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C) 16π ft

Step-by-step explanation:

Fencing is perimeter.  The perimeter of a circle is the circumference.

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4 0
3 years ago
Read 2 more answers
Rename 600,000= ten thousands
lyudmila [28]

For this case we have the following number:

600,000

We can rewrite this number as the product of two numbers.

We have then, mathematically:

600,000 = 60 * 10,000

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Answer:

Rewriting 600,000 we have:

600,000 = sixty - ten thousands

4 0
3 years ago
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The cost of having photos taken includes a sitting fee and $12 for each portrait. The cost of 3,6, and 9 photos respectively is
Eddi Din [679]

Answer:The sitting fee is 15 dollars


Step-by-step explanation:If you were to use the formula y=mx+b then the starting equation would be y=12x+b. It already gave you the cost for the amount of photos respectively so 51=12(3)+b. 12 times 3 equals 36 and 51 minus 36 equals 15. The same way would be used for 87 dollars and 123 dollars while using the amount of photos respectively. 87=12(6)+b. 12 times 6 equals 72. 72 plus 15 equals 87. 123=12(9)+b. 12 times 9 equals 108. 108 plus 15 equals 123. Therefore the sitting fee is 15. (51=12(3)+15, 87=12(6)+15, 123=12(9)+15)


4 0
3 years ago
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