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Alchen [17]
3 years ago
11

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e.

inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________
Mathematics
1 answer:
zaharov [31]3 years ago
3 0

Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:_Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:______________QuQuestion

Show that for a square Question Question

Show that for a square symmetric matrix M, Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________tric mQuestion

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________atrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________estion

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:______________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:__________________

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A lighthouse casts a shadow 32 meters long at the same time a nearby statue casts a shadow that is 9 meters long. If the statue
Pavlova-9 [17]

Answer:

40

Step-by-step explanation:

Ok, so basically let's start with a proportion.

x/32 = 11.25/9

Cross multiply:

x * 9 = 32 * 11.25

9x = 32 * 11.25

9x = 360

Solving for variable 'x'.

Divide each side by '9'.

x = 40

I don't know if this is the correct answer, but it was based on my math. I hope this helps!

5 0
3 years ago
Mindy has $10.75 to buy school supplies. She spends $3.96 at one store for a package of glue sticks, but she still needs to buy
maks197457 [2]
She can only spend $2.62
5 0
3 years ago
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HELP PLEASE
Gnesinka [82]

Answer: x^2=8y


Step-by-step explanation:

Let the given parabolic mirror opens upwards and vertex=(0,0)

Focus point of the parabolic mirror is located 2 inches from the vertex of the mirror.  ∴ p=2

Since, the parabola opens upward, then the equation of the parabola is of the form x^2=4py

Substitute the value of p=2 in this, we get the equation of the parabolic mirror

x^2=4(2)y\\\Rightarrow\ x^2=8y

Hence, the equation of the parabola that models the cross section of the mirror is x^2=8y

7 0
3 years ago
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PLEASE HELP IT"S URGENT <br> Which figure has the greater Volume??
Aneli [31]
I cannot see the picture ?
6 0
3 years ago
Kenneth Drew a scale drawing of an apartment the scale of the drawing was 2 meters:1 meter the living room is 6 m long in real l
atroni [7]

Answer:

3 meters

Step-by-step explanation:

Given the scale drawing :

2m : 1m

Length of living room in real life = 6 m long

2 meter = 1 meter

Real life = scale drawing

If length = 6 meter long ;

using cross multiplication :

2 meter = 1 meter

6 meter = x

2x = 6

x = 6/2

x = 3 meter

Length of living room in drawing = 3 meters

3 0
3 years ago
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