X = 112
Sorry I had to smoosh the image so it would fit.
Answer:
Mass
Step-by-step explanation:
For this problem, the confidence interval is the one we are looking
for. Since the confidence level is not given, we assume that it is 95%.
The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n
Where:
<span>
</span>
α= 5%
α/2
= 2.5%
t
0.025, 19 = 2.093 (check t table)
n
= 20
df
= n – 1 = 20 – 1 = 19
So plugging in our values:
8.41 ± 2.093 * 0.77 √ 1 + 1/20
= 8.41 ± 2.093 * 0.77 (1.0247)
= 8.41 ± 2.093 * 0.789019
= 8.41 ± 1.65141676
<span>= 6.7586 < x < 10.0614</span>
as we know that <span>If the 4" side of the card was scaled up to 10.5
then the scaling factor is 10.5/4 = 2.625.
The 5 side would be the length 5 x 2.625 = 13.125 which exceeds the maximum dimension of 11.
Thus, it is the 5 side which is scaled up to 10.5 and the scaling factor is therefore 10.5/5 = 2.1.
The scaled up length of the 4 side is thus 4 x 2.1 = 8.4.</span>