M= (7-1)/(2-0)=3
y=3x + c
plug in Q
1= 3 x 0 +c
=> c =-2
=> the equation represents line QR is y=3x -2
The average rate of change of <em>f(x)</em> on -3 ≤ <em>x</em> ≤ 3 is given to be
(<em>f</em> (3) - <em>f</em> (-3)) / (3 - (-3)) = -2.5
If <em>f</em> (-3) = 14, then
(<em>f</em> (3) - 14) / (3 + 3) = -2.5
(<em>f</em> (3) - 14) / 6 = -2.5
<em>f</em> (3) - 14 = -15
<em>f</em> (3) = -1
Answer: I think u have to multiply all da numbers.
Step-by-step explanation:
Answer:
Suppose N is the size of a population of radioactive atoms at a given time t, and dN is the amount by which the population decreases in time dt; then the rate of change is given by the equation dN/dt = −λN, where λ is the decay constant.
