Option A
The restaurant Manager can afford at most 10 employees for the day
<em><u>Solution:</u></em>
Given that restaurant manager can spend at most $600 a day for operating costs and payroll
It costs $100 each day to operate the bank and $50 dollars a day for each employee
The given inequality is:
Where , "x" is the number of employees per day
Let us solve the inequality for "x"
Add -100 on both sides of inequality
Divide by 50 on both sides of inequality
Hence the restaurant Manager can afford at most 10 employees for the day
Thus option A is correct
Answer:
He can print 62 documents
Step-by-step explanation:
500/8=62.5
He can print only 62 documents because he cannot print half a document.
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Answer:
The equation you are given is a quadratic. The standard form of a quadratic is y = a(x-h)2 + k where (h,k) is the vertex of the graph, which is a parabola. Vertically moving the graph 4 units upward means that you are moving k +4 units.
y = a(x-h)2 + k standard form
y = 5x2 - 4 original equation
y = 5(x-0)2 - 4 re-written in standard form
h = 0 k = -4
Four (4) units up is k + 4--->-4 + 4 = 0.
Therefore, f(x) = 5x2 + 0--->f(x) = 5x2.
Step-by-step explanation:
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Answer:
The initial value is $78
Step-by-step explanation:
Given
(weekly)
Required
Determine the initial value
The initial value is the amount he has in its bank account before making his weekly savings.
From the question, we have that his initial balance is $78.
Hence, the initial value is $78
However, his weekly balance can be expressed as:
Represent number of weeks with x; So, we have:
12 red counters
7 more red counters than yellow counters
12 - 7 = 5 yellow counters
Dara has 5 yellow counters.
