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blsea [12.9K]
3 years ago
11

Calculate the area of the irregular polygon shown below:

Mathematics
2 answers:
nlexa [21]3 years ago
5 0
Area of the polygon = multiply all sides
10 * 5 * 4 * 3 * 4 * 3 * 5 = 36000in^2

Answer = 36000in^2
mr Goodwill [35]3 years ago
3 0

Answer:

26 in²

Step-by-step explanation:

If we consider the outside rectangle, then subtract the 2 congruent white rectangles.

Area of outside rectangle = 10 × 5 = 50 in²

Area of 2 white rectangles = 2 × 4 × 3 = 24 in²

Thus the area of the E shape = 50 - 24 = 26 in²

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These are the two equation

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What is seen in the middle of March and April that can’t be seen at the beginning or end of either month?
Troyanec [42]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu
AURORKA [14]

Answer:

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21        x2`= 27

n1=  10       n2= 14

s1= 5.6       s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27)  +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

- 1.5479 < u1-u2 <  10.4521

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`)  /√s1²/n1 + s2²/n2

t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

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3 years ago
A horse can run 1 3/8 of a mie in 1 3/5 minute. how long does it take the horse to run 1 mile
mario62 [17]

A horse can run 1 3/8 of a mile in 1 3/5 minute. How long does it take the horse to run 1 mile?

So what i would personally do first is convert the fractions into decimals.

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1 3/5= 8/5 =1.6         of a minute

Now we find the rate of change

I

8 0
2 years ago
Urgent Need Help! worth 100 points
Natali [406]

the answer to your question is 4 times 6, 4 times 3 + 4 times 3

have a nice day

4 0
3 years ago
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