(cube root of 5) * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)
This becomes easier if we switch to fractional exponents:
5^(1/3) * 5^(1/2) 5^(1/3 + 1/2) 5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3) 5^(5/3) 5^(5/3)
Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.
1
Thus, 5^[5/6 - 5/3] = 5^(-5/6) = --------------
5^(5/6)
That's the correct answer. But if you want to remove the fractional exponent from the denominator, do this:
1 5^(1/6) 5^(1/6)
---------- * ------------- = -------------- (ANSWER)
5^(5/6) 5^(1/6) 5
G. The shape would be similar since dilation at the origin is just a translation and a translation doesn't affect the shape's size or shape.
h. They will still be similar because adding length to each side will just make the shape larger, and if the shape hasn't changed (which it hasn't) it will remain similar.
I. This is simple, just write an equation of the changes you could do the shape and it would be similar. You would have to explain how many you should move and from which sides (should be all sides). It is better for you to do this because there are millions of possible equations, and if you use the same one then it might be striked.
Answer:
d≈7.07
Step-by-step explanation:
Using the formulas
P=4a
d= \sqrt{2} a
Solving ford
d= \sqrt{2} P/4=2·20
/4≈7.07107
Answer:
750
Step-by-step explanation:
10 times 5 times 15
Answer: the quantity of matter which a body contains, as measured by its acceleration under a given force or by the force exerted on it by a gravitational fieldStep-by-step explanation:
