Answer:
Step-by-step explanation:
<u>f is continuous</u> because is the composition of two continuous functions:
(it is continuous in the real numbers)
(it is continuous in the domain (0,1))
<u>It is bounded</u> because 
<u>And it is not uniformly continuous</u> because we can take 
in the definition. Let 
we will prove that there exist a pair 
such that 
and 
.
Now, by the archimedean property we know that there exists a natural number N such that
.
Let's take 
and 
. We can see that
And also:
And we conclude the proof.
Answer:
Input Data :
Point 1(xA,yA)(xA,yA) = (4, 3)
Point 2(xB,yB)(xB,yB) = (3, -2)
Objective :
Find the distance between two given points on a line?
Formula :
Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2
Solution :
Distance between two points = √(3−4)2+(−2−3)2(3-4)2+(-2-3)2
= √(−1)2+(−5)2(-1)2+(-5)2
= √1+251+25
= √2626 = 5.099
Distance between points (4, 3) and (3, -2) is 5.099
Answer:
3rd option
Step-by-step explanation:
Standard for is x × 10 ^I
where,
I = indice
10 > x < 0
you cannot write this is standard form with putting in what they stand for. However you can simplify it -
4(8m-7n) +6(3n-4m)
32m - 28n + 18n - 24m
8m - 10n
but hey I am from England do what we call standard form might be different
$150 divided amongst himself and friends (3) which equals 50, so add $50 to Sam’s share.
