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3 years ago

HELP ITS ALGEBRA 2!!

Mathematics

1 answer:

Orlov [11]3 years ago

5 0

To find the rate of change, do:
$\frac{ y_{1} - y_{2} }{ x_{1} - x_{2} }$

1) 4-2 / 2-1 = 2

2) 8-4 / 3-2 = 4

3) 16-8 / 4-3 = 8

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Klio2033 [76]

2 out of 4 statements supported the data above. This are:

JP Morgan Chase Tower has more height per story than the Key Tower.

- This is true. Comparing the height in ft, JP Morgan Chase has a height of 1,002 ft. It is higher than the Key tower which is 947 ft only.

The Key Tower has the least height per story.

- Looking at its height, this is the least. It only stands at 947 ft as compared to others that are more than 1,000 ft

6 0

3 years ago

Please help. 10 points and brainliest.

Snezhnost [94]

Answer:

$\frac{a^2}{b^2}$

Step-by-step explanation:

Apply the exponent rule $a^b*a^c=a^b+c$ to a

$a^4*a^-^2=a^4^-^2=a^2$

$b^3a^2b^-^5$

Apply the exponent rule to b

$b^3*b^-^5=b^3^-^5=b^-^2$

Apply the exponent rule $a^-^b=\frac{1}{a^b}$

$b^-^2=\frac{1}{b^2}=\frac{1}{b^2}a^2=\frac{a^2}{b^2}$

6 0

3 years ago

Compare the line passing through the points (–2, –9) and (4, 6) to the line given by the equation y = 25x – 4.

elena-s [515]

Answer:

D. They have the same y-intercep

Step-by-step explanation:

Before the comparison will be efficient, let's determine the equation of the two points and the x intercept .

(–2, –9) and (4, 6)

Gradient= (6--9)/(4--2)

Gradient= (6+9)/(4+2)

Gradient= 15/6

Gradient= 5/2

Choosing (–2, –9)

The equation of the line

(Y+9)= 5/2(x+2)

2(y+9)= 5(x+2)

2y +18 = 5x +10

2y =5x -8

Y= 5/2x -4

Choosing (4, 6)

The equation of line

(Y-6)= 5/2(x-4)

2(y-6) = 5(x-4)

2y -12 = 5x -20

2y = 5x-8

Y= 5/2x -4

From the above solution it's clear that the only thing the both equation have in common to the given equation is -4 which is the y intercept

4 0

3 years ago

Translate (-5,-3) and then reflect over the x-axis

katrin2010 [14]

Would it be (5,3) reflected?

5 0

3 years ago

jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h. At 8.30a.m. Sipho left town A to trave

7nadin3 [17]

Answer:

Sipho catches up Jabu at 6:30 pm

Step-by-step explanation:

Jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h.

At 8:30 am, when Sipho leaves, we will have traveled 2.5 hours at 80 km/h, so he will be 80*2.5 = 200 km ahead.

From then, his position will be given by:

$J(t) = 200 + 80t$

Sipho left town A to travel to town B. He drove at an average speed of 100 km/h.

His position will be given by:

$S(t) = 100t$

At what time will Sipho catch up jabu?

He will catch up in t hours, and t is found when:

$S(t) = J(t)$

$100t = 200 + 80t$

$20t = 200$

$t = \frac{200}{20} = 10$

He will catch up 10 hours after 8:30 am, that is, 6:30 pm.

Sipho catches up Jabu at 6:30 pm

4 0

2 years ago