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chubhunter [2.5K]
3 years ago
10

Use the quadratic formula to find the solutions to the quadratic equation below x^2-7x-3=0

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

the roots are \frac{7+\sqrt{61} }{2} and \frac{7-\sqrt{61} }{2}

Step-by-step explanation:

here we use Shridhar acharya formula

if ax^{2} + bx +c = 0 is the quadratic equation

the the roots are , \frac{-b +\sqrt{b^{2-4ac} } }{2a} and \frac{-b -\sqrt{b^{2-4ac} } }{2a}

comparing with the equation we get a=1 b= -7 c = -3

hence the roots are \frac{7 +\sqrt{7^{2-4X1X(-3)} } }{2X1} and \frac{7 -\sqrt{7^{2-4X1X(-3)} } }{2X1}

= \frac{7+\sqrt{61} }{2} and \frac{7-\sqrt{61} }{2}

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