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chubhunter [2.5K]
3 years ago
10

Use the quadratic formula to find the solutions to the quadratic equation below x^2-7x-3=0

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

the roots are \frac{7+\sqrt{61} }{2} and \frac{7-\sqrt{61} }{2}

Step-by-step explanation:

here we use Shridhar acharya formula

if ax^{2} + bx +c = 0 is the quadratic equation

the the roots are , \frac{-b +\sqrt{b^{2-4ac} } }{2a} and \frac{-b -\sqrt{b^{2-4ac} } }{2a}

comparing with the equation we get a=1 b= -7 c = -3

hence the roots are \frac{7 +\sqrt{7^{2-4X1X(-3)} } }{2X1} and \frac{7 -\sqrt{7^{2-4X1X(-3)} } }{2X1}

= \frac{7+\sqrt{61} }{2} and \frac{7-\sqrt{61} }{2}

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Paraphin [41]

Answer:

2\frac{1}{6} pounds.

Step-by-step explanation:

We have been given that Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6.

To find weight of bucket after taking out the two items, we will subtract weight of each item from 6 pounds as:

\text{Weight of bucket}=6-1\frac{4}{6}-2\frac{1}{6}

Let us convert mixed fractions into improper fractions as:

1\frac{4}{6}=\frac{6\cdot 1+4}{6}=\frac{10}{6}\\\\2\frac{1}{6}=\frac{6\cdot 2+1}{6}=\frac{12+1}{6}=\frac{13}{6}

\text{Weight of bucket}=6-\frac{10}{6}-\frac{13}{6}

\text{Weight of bucket}=\frac{6\cdot 6}{6}-\frac{10}{6}-\frac{13}{6}

\text{Weight of bucket}=\frac{36}{6}-\frac{10}{6}-\frac{13}{6}

Combine numerators:

\text{Weight of bucket}=\frac{36-10-13}{6}

\text{Weight of bucket}=\frac{13}{6}

\text{Weight of bucket}=2\frac{1}{6}

Therefore, the weight of the bucket is 2\frac{1}{6} pounds.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

It is given that ray PT is the angle bisector of angle RPS. It means PT divides the angle RPS in two equal parts.

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Now, it is clear that

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