Question

Use the quadratic formula to find the solutions to the quadratic equation below x^2-7x-3=0

Answer 1

the roots are $\frac{7+\sqrt{61} }{2}$ and $\frac{7-\sqrt{61} }{2}$

Step-by-step explanation:

here we use Shridhar acharya formula

if a$x^{2}$ + bx +c = 0 is the quadratic equation

the the roots are , $\frac{-b +\sqrt{b^{2-4ac} } }{2a}$ and $\frac{-b -\sqrt{b^{2-4ac} } }{2a}$

comparing with the equation we get a=1 b= -7 c = -3

hence the roots are $\frac{7 +\sqrt{7^{2-4X1X(-3)} } }{2X1}$ and $\frac{7 -\sqrt{7^{2-4X1X(-3)} } }{2X1}$

= $\frac{7+\sqrt{61} }{2}$ and $\frac{7-\sqrt{61} }{2}$