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3 years ago

12

Solve for x: −4|x + 5| = −16

1 answer:

katrin2010 [14]3 years ago

4 0

X1= -9, x2 = -1. sooo the third one

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Please help. i don't understand

zaharov [31]

78×.33=25.74 busses are new

25.74+15=40.74 new busses

78+15=93 total busses

40.74/78=0.5223076923= 52% will be new with the new 15 busses

4 0

3 years ago

X + 6 = 4X/7<br> Solve for X<br><br> Will give brainliest to the person who helps and explains

Citrus2011 [14]

Answer:

x = -14

Step-by-step explanation:

x + 6 = 4x/7

7x + 42 = 4x

7x - 4x = -42

3x = -42

x = -42 ÷ 3

x = -14

8 0

2 years ago

What value of c makes x2 − 12x + c a perfect square trinomial? −36 −24 24 36

rewona [7]

Take half of the middle coefficient.
Then square it.

-12/2 = -6

(-6)^2 = 36

c = 36

8 0

3 years ago

Read 2 more answers

Trapezoids and kites

lisov135 [29]

QUESTION 3

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 36\degree +70\degree+m$ .

$\Rightarrow 106\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles of the kite are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 4

RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.

Using the Pythagoras Theorem, we obtain;

$|RH|^2=12^2+20^2$

$|RH|^2=144+400$

$|RH|^2=544$

$|RH|=\sqrt{544}$

$|RH|=4\sqrt{34}$

QUESTION 5

The given figure is an isosceles trapezium.

The base angles of an isosceles trapezium are equal.

Therefore $m$

QUESTION 6

The measure of angle Y and Z are supplementary angles.

The two angles form a pair of co-interior angles of the trapezium.

This implies that;

$m$

$\Rightarrow m$

$\Rightarrow m$

QUESTION 7

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 48\degree +110\degree+m$ .

$\Rightarrow 158\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 8

The diagonals of the kite meet at right angles.

The length of BC can also be found using Pythagoras Theorem;

$|BC|^2=4^2+7^2$

$\Rightarrow |BC|^2=16+49$

$\Rightarrow |BC|^2=65$

$\Rightarrow |BC|=\sqrt{65}$

QUESTION 9.

The sum of the interior angles of a trapezium is $360\degree$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the measure of angle M and K are congruent.

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

6 0

3 years ago

Help me pls i have been stuck on this for the past hour

Sedbober [7]

Answer:

-4, -6, -3, -5, -1. The inequality solved for n is n ≥ -6.

Step-by-step explanation:

Substitute all the values in the equation.

n/2 ≥ -3

-10/2 ≥ -3

-5 is not ≥ -3.

n/2 ≥ -3

-7/2 ≥ -3

-3.5 is not ≥ -3.

n/2 ≥ -3

-4/2 ≥ -3

-2 is ≥ -3.

n/2 ≥ -3

-9/2 ≥ -3

-4.5 is not ≥ -3.

n/2 ≥ -3

-6/2 ≥ -3

-3 is ≥ -3.

n/2 ≥ -3

-3/2 ≥ -3

-1.5 is ≥ -3.

n/2 ≥ -3

-8/2 ≥ -3

-4 is not ≥ -3.

n/2 ≥ -3

-5/2 ≥ -3

-2.5 is ≥ -3.

n/2 ≥ -3

-2/2 ≥ -3

-1 is ≥ -3.

To solve the inequality n/2 ≥ -3 for n, do these steps.

n/2 ≥ -3

Multiply by 2.

n ≥ -6.

3 0

3 years ago