Answer:
see attached
Step-by-step explanation:
In the attached, the feasible region is white, and all excluded regions are shaded. When there are so many inequalities, it is easier to see the solution (feasible region) this way. The boundary lines are dashed because they are not excluded. That is, each boundary line is part of the feasible region.
The vertices of the feasible region are shown to aid in any optimization you might want to do. We have shown the values that would apply if there were a constraint y ≥ 0, which is not on your list. (We assume pounds of Brussels sprouts will not be negative.)
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If you actually do the shading required by the problem statement, you will be shading on the opposite side of each of the lines shown, and you would draw the lines as solid.
Answer:
3:45 PM.
Step-by-step explanation:
We have been given that on Thursday afternoon at camp Alice played basketball and went swimming before dinner she spent 45 minutes playing basketball and one hour swimming dinner lasted for an hour. The dinner ended at 5:30 PM.
Since she spent 1 hour for swimming, so 1 hour before 5:30 PM would be 4:30 PM.
To find the time, when Alice started playing basketball, we need to find 45 minutes before 4:30 PM.
30 minutes before 4:30 PM would be 4:00 PM and 15 minutes before 4:00 PM would be 3:45 PM.
Therefore, Alice started playing basket ball at 3:45 PM.
Answer:
RT = 12 units
Step-by-step explanation:
From the figure attached,
ΔSRQ is right triangle.
m∠R = 90°
An altitude has been constructed from point T to side SQ.
m∠RTQ = 90°
By applying geometric mean theorem in triangle SRQ,
![\frac{\text{RT}}{\text{ST}}=\frac{\text{TQ}}{\text{RT}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BRT%7D%7D%7B%5Ctext%7BST%7D%7D%3D%5Cfrac%7B%5Ctext%7BTQ%7D%7D%7B%5Ctext%7BRT%7D%7D)
![\frac{x}{9}=\frac{16}{x}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B9%7D%3D%5Cfrac%7B16%7D%7Bx%7D)
x² = 16 × 9
x² = 144
x = √144
x = 12
Therefore, length of altitude RT is 12 units.
Answer:
provide the value of B and C