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ahrayia [7]
3 years ago
8

Factor 26r3s + 52r5 - 39r2s4

Mathematics
1 answer:
aniked [119]3 years ago
4 0
Hello,

26r^3s+52r^5-39r²s^4
=13r²(4r^3+2rs-3s^4)

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Please help!! MathsWatch, Surd Expressions, Clip 207c
dexar [7]

Answer:

A=(72+36\sqrt{3})\ mm^2

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

b=AB+BC+CD+DE ----> by segment addition postulate

substitute

b=3+3+3+3=12\ mm

step 2

Find the height of rectangle

a=FB+CG+GH ---> by segment addition postulate

substitute the given values

a=3+CG+3\\a=6+CG

Find the length sides CG

Applying the Pythagorean Theorem

BG^2=BC^2+CG^2

substitute the given values

6^2=3^2+CG^2

CG^2=6^2-3^2

CG=\sqrt{27}\ mm

simplify

CG=3\sqrt{3}\ mm

therefore

a=(6+3\sqrt{3})\ mm

step 3

Find the area of rectangle

A=ab

we have

a=(6+3\sqrt{3})\ mm

b=12\ mm

substitute

A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2

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Only square matrices have multiplicative identities. True or false
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Step-by-step explanation:

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