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Vsevolod [243]
3 years ago
13

The birth rate of a population is b(t) = 2300e0.024t people per year and the death rate is d(t)= 1450e0.019t people per year, fi

nd the area between these curves for 0 ≤ t ≤ 10. (Round your answer to the nearest integer.)
Mathematics
1 answer:
Shalnov [3]3 years ago
4 0

Answer:

Area = 10025.66 square units

Step-by-step explanation:

We are given the following in the question:

The birth rate of a population:

b(t) = 2300e^{0.024t}

The death rate of a population:

d(t)= 1450e^{0.019t}

The area between the curve for 0 ≤ t ≤ 10, is given by:

\displaystyle\int_0^{10}b(t) - d(t)~ dt\\\\\displaystyle\int_0^{10} 2300e^{0.024t}-1450e^{0.019t}~dt\\\\= \Bigg[\frac{2300e^{0.024t}}{0.024}\Bigg]_0^{10}-\Bigg[\frac{1450e^{0.019t}}{0.019}\Bigg]_0^{10}\\\\= \Bigg[\frac{2300e^{0.24}}{0.024}-\frac{1450e^{0.19}}{0.019}\Bigg]-\Bigg[\frac{2300}{0.024}-\frac{1450}{0.019}\Bigg]\\\\= 29543.2058565 - 19517.5438596 \approx 10025.6

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The increasing annual cost (including tuition, room, board, books, and fees) to attend college has been widely discussed (Time).
NeX [460]

Answer:

(a) PRIVATE COLLEGES

Sample mean is $42.5 thousand

Sample standard deviation is $6.65 thousand

PUBLIC COLLEGES

Sample mean is $22.3 thousand

Sample standard deviation is $4.34 thousand

(b) Point estimate is $20.2 thousand. The mean annual cost to attend private colleges ($42.5 thousand) is more than the mean annual cost to attend public colleges ($22.3 thousand)

(c) 95% confidence interval of the difference between the mean annual cost of attending private and public colleges is $19.2 thousand to $21.2 thousand

Step-by-step explanation:

(a) PRIVATE COLLEGES

Sample mean = Total cost ÷ number of colleges = (51.8+42.2+45+34.3+44+29.6+46.8+36.8+51.5+43) ÷ 10 = 425 ÷ 10 = $42.5 thousand

Sample standard deviation = sqrt[summation (cost - sample mean)^2 ÷ number of colleges] = sqrt([(51.8-42.5)^2 + (42.2-42.5)^2 + (45-42.5)^2 + (34.3-42.5)^2 + (44-42.5)^2 + (29.6-42.5)^2 + (36.8-42.5)^2 + (51.5-42.5)^2 + (43-42.5)^2] ÷ 10) = sqrt (44.24) = $6.65 thousand

PUBLIC COLLEGES

Sample mean = (20.3+22+28.2+15.6+24.1+28.5+22.8+25.8+18.5+25.6+14.4+21.8) ÷ 12 = 267.6 ÷ 12 = $22.3 thousand

Sample standard deviation = sqrt([(20.3-22.3)^2 + (22-22.3)^2 + (28.2-22.3)^2 + (15.6-22.3)^2 + (24.1-22.3)^2 + (28.5-22.3)^2 + (22.8-22.3)^2 + (25.8-22.3)^2 + (18.5-22.3)^2 + (25.6-22.3)^2 + (14.4-22.3)^2 + (21.8-22.3)^2] ÷ 12) = sqrt (18.83) = $4.34 thousand

(b) Point estimate = mean annual cost of attending private colleges - mean annual cost of attending public colleges = $42.5 thousand - $22.3 thousand = $20.2 thousand.

This implies the the mean annual cost of attending private colleges is greater than the mean annual cost of attending public colleges

(c) Confidence Interval = Mean + or - Margin of error (E)

E = t×sd/√n

Mean = $42.5 - $22.3 = $20.2 thousand

sd = $6.65 - $4.34 = $2.31 thousand

n = 10+12 = 22

degree of freedom = 22-2 = 20

t-value corresponding to 20 degrees of freedom and 95% confidence level is 2.086

E = 2.086×$2.31/√22 = $1.0 thousand

Lower bound = Mean - E = $20.2 thousand - $1.0 thousand = $19.2 thousand

Upper bound = Mean + E = $20.2 thousand + $1.0 thousand = $21.2 thousand

95% confidence interval is $19.2 thousand to $21.2 thousand

6 0
3 years ago
If street lights are placed at most 145
Paraphin [41]

Answer:

Step-by-step explanation:

d=4 miles=4×1760 yards=7040 yards=7040×3 ft

number of lights=21120 ft

number of lights=21120/145 +1≈145.7+1=146+1=147 lights

7 0
2 years ago
What is the equation in slope-intercept form of the line that passes through the point (5,0) and is parallel to the line represe
zlopas [31]

Answer:

y=1.2x-6

Step-by-step explanation:

place in the points

0=1.2(5)+b

distrubutive property

0=6+b

subtract 6 on both sides

-6=b

y=1.2x-6

6 0
3 years ago
Simplify and solve for the given variable. <br>Solve 19x = 3 + 4(x + 6) - 2<br>for X.​
Rom4ik [11]

Answer:

5/3

Step-by-step explanation:

19x=3+4(x+6)-2

19x=3+4x+24-2

19x-4x=3+24-2

15x=27-2

15x=25

x=25/15

simplify

x=5/3

5 0
3 years ago
Pls help with algebra!
Serjik [45]
Part A: This data does represent a function because no value of x is repeated.
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Part C: If f(x) is equal to 6 then x will equal 3
4 0
3 years ago
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