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netineya [11]
4 years ago
9

HELP ASAP please i cant seem to get out of this question its hard!!!!1111!!!!1!!

Mathematics
1 answer:
zvonat [6]4 years ago
7 0
I think it is A. -7

I think that because FG's distance is 6, and if FG and HI are equal, then their distances should both be equal to 6.
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Solve for y: y+4 = -2(x – 6)​
WITCHER [35]
Y=-2x+8
l hope that helps
4 0
3 years ago
Can someone help me here pls thanks!​
vesna_86 [32]

Using proportions, it is found that the measure of the inscribed angle B is of 30º.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In a circle, the inscribed angle is half the measure of the outside angle. Hence, in this problem, the measure of angle B is of 50% of 60º, hence:

m<B = 0.5 x 60º = 30º.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

4 0
2 years ago
H(n) = -2n² + 4; Find h(4)<br>A.-28<br>B.68<br>C.28<br>D.-4​
Elena L [17]

Answer:

-28

Step-by-step explanation:

h(4)=-2(4)^2+4

-32+4=-28

7 0
3 years ago
Suppose you invest $7500 at an annual interest rate of 4.2% compounded continuously. How much will you have in the account after
tatyana61 [14]
<span>Interest=principle x rate x time (in years)
so putting values so
Interest=7500 (.042)(2)
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6 0
3 years ago
0-6
dybincka [34]
<h3>Given :-</h3>
  • Pranav ran 20.3 km more than Branda

  • Pravin ran 38.6 km

\\  \\

To find :

  • No. of kilometers did Brenda run.

\\  \\

<h3>Let :</h3>

  • No. of kilometers ran by Brenda be x.

\\  \\

<h3>Solution:</h3>

\\  \\

Equation formed:-

\\  \\

Total distance covered by Pravan = More distance covered by Pravan + distance covered by Brenda.

Therefore:-

\\  \\

\leadsto \sf38.6 = 20.3 + x

Write the equation

\\  \\

\leadsto \sf38.6 - 20.3 =x

When we transfer 20.3 to left side the positive sign (+) will change into negative sign (–)

\\  \\

\leadsto \sf x = 38.6 - 20.3

Arrange the equation because x is always represented at left side.

\\  \\

\leadsto \boxed {\pmb{\sf x = 18.3}}\star

After subtracting 38.6 with 20.3 we will get result as 18.3 .

\\  \\

\therefore \red{ \underline{  \pmb{\frak{Distance  ~ covered ~by ~Brenda~ is ~equal ~to~18.3~kilometers}}}}

7 0
3 years ago
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