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Sidana [21]
3 years ago
11

A baby gains 11 pounds in its first year of life. The baby gained 4 1/4 pounds during the first four months and 3 1/2 pounds in

its second four months. How much did the baby gain in the last four months?
Mathematics
2 answers:
prohojiy [21]3 years ago
7 0
Amount of weight gain in first year = 11 pounds

A year can be divided into three parts consisting of four months each.

According to the question;

The baby gained 4 1/4 pounds during the first four months and 3 1/2pounds in its second four months.

Let weight gained in third 4 month be 'x' pounds.

So;

=> Weight gained in first year = Weight gained in first 4 months + Weight gained in second 4 months + Weight gained in third 4 months

=> 11 pounds = 4.25 pounds + 3.5 pounds + x pounds.

=> x pounds = 11 pounds - 7.75 pounds

=> x pounds = 3.25 pounds

Therefore, the baby gain 3.25 pounds in the last four months.
xeze [42]3 years ago
5 0
The baby gains 3.25lbs in the last 4 months. 

This problem can be solved by simple subtraction. Take the total amount and subtract the 4 month increments in order to find the find 4 months. 

Total = 1st 4 months + 2nd 4 months + 3rd 4 months

11 = 4.25 + 3.5 + 3rd 4 months

11 = 7.75 + 3rd 4 months

3.25 = 3rd 4 months
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Answer:  The area of the parallelogram is:
_______________________________________________________
\frac{9393}{8}  in² = 1174 ⅛  in² = 1174.125 in² .
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
 A = base * height = b * h ;

From the figure (from the actual "question"):
_______________________________________
         b = 50.5 in.

         h = 23.25 in.
____________________________________________________________
Method 1)  A = b * h =
                 
                     =  (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as:  1174 <span>⅛ .
</span>____________________________________________________________
Method 2)  A = b * h =
             
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</span>___________________________________________________________
Note:  "50 ½ " = [(50*2) + 1 ] / 2  = \frac{101}{2} ;

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____________________________________________________________
→  A =  (\frac{101}{2} in) * (\frac{93}{4} in) ;
 
→  A = \frac{(101*93)}{(2*4)}  in² = \frac{9393}{8}  in² ; 
          
→  A = (9393/8) in² =  
         
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________________________________________________________
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