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Sidana [21]
3 years ago
11

A baby gains 11 pounds in its first year of life. The baby gained 4 1/4 pounds during the first four months and 3 1/2 pounds in

its second four months. How much did the baby gain in the last four months?
Mathematics
2 answers:
prohojiy [21]3 years ago
7 0
Amount of weight gain in first year = 11 pounds

A year can be divided into three parts consisting of four months each.

According to the question;

The baby gained 4 1/4 pounds during the first four months and 3 1/2pounds in its second four months.

Let weight gained in third 4 month be 'x' pounds.

So;

=> Weight gained in first year = Weight gained in first 4 months + Weight gained in second 4 months + Weight gained in third 4 months

=> 11 pounds = 4.25 pounds + 3.5 pounds + x pounds.

=> x pounds = 11 pounds - 7.75 pounds

=> x pounds = 3.25 pounds

Therefore, the baby gain 3.25 pounds in the last four months.
xeze [42]3 years ago
5 0
The baby gains 3.25lbs in the last 4 months. 

This problem can be solved by simple subtraction. Take the total amount and subtract the 4 month increments in order to find the find 4 months. 

Total = 1st 4 months + 2nd 4 months + 3rd 4 months

11 = 4.25 + 3.5 + 3rd 4 months

11 = 7.75 + 3rd 4 months

3.25 = 3rd 4 months
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Answer:

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then:

(3x-70) + (3y+40) + 120 + x = 360     ⇒ first eq.

(3y+40) + (3x-70) = 180      ⇒  second eq

development:

from the first eq.

3x + x + 3y  =  360  + 70 - 40 - 120

4x + 3y = 430 - 160

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3y = 270 - 4x

y = (270 - 4x) / 3    ⇒  fourth eq.

from the secon eq.:

3y + 3x = 180 + 70 - 40

3y + 3x = 250 - 40

3y + 3x = 210    ⇒  fifth eq.

multiply by -1  the fifth eq and sum with the third eq.

  -3y  - 3x = -210    ⇒   (fifth eq. *-1)

   3y  + 4x = 270

⇒  0   +  x  = 60

x = 60°

from the fourth eq.

y = (270-4x)/3

y = (270-(4*60)) / 3

y = (270 - 240) / 3

y = 30/3

y = 10°

Probe:

from the first eq.

(3x-70) + (3y+40) + 120 + x = 360

3*60 - 70 + 3*10 + 40 + 120 + 60 = 360

180 - 70 + 30 + 40 + 120 + 60 = 360

180 + 30 + 40 + 120 + 60 - 70 = 360

430 - 70 = 360

Answer:

y = 10

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Answer:

For 3x^2+4x+4=0

Discriminant= = -32

The solutions are

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The solutions

(-b+√x)/2a= (-1+√-11)/3

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For 9x^2-6x+2=0

Discriminant= -36

The solutions

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a= (1-√-1)/3

Step-by-step explanation:

Formula for the discriminant = b²-4ac

let the discriminant be = x for the equations

The solution of the equations

= (-b+√x)/2a and = (-b-√x)/2a

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Discriminant= 4²-4(3)(4)

Discriminant= 16-48

Discriminant= = -32

The solutions

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(-b-√x)/2a= (-4 -4√-2)/6

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= 2²-4(3)(4)

Discriminant= 4-48

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(-b+√x)/2a= (-2 +2√-11)/6

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Discriminant= 36 -72

Discriminant= -36

The solutions

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(-b+√x)/2a= (6 +6√-1)/18

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a =( 6-√-36)/18

(-b-√x)/2a= (6 -6√-1)/18

(-b-√x)/2a= (1-√-1)/3

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3 years ago
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