The simplified form of this polynomial is (n(20n + 1))/5
What is 20 to the square root of 10?
1 answer:
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The answer to the above question can be determined as -
Let the point on the left side of P be Q, thus coordinates of Q are (a,1) and point on the right side of P be R, thus coordinates of R will be, (a+4, 1).
Now, it given that, between x coordinates of Q and R is 4, and it can be seen that they are getting divided into half.
So, the x coordinate of P will be - a + i.e. a + 2
<u>Thus, the x coordinate of P will be a +2.</u>
To calculate the square root, you can either use the √symbol on a calculator or you can manually find it using Prime Factorization. For non-perfect squares, Prime Factorization is the way to go.
The first two steps work for solving large perfect squares as well.
1. Divide your number into perfect square factors.
2. Take the square roots of your perfect square factors.
3. If your number doesn't factor perfectly, reduce your answer to simplest terms.
4. If needed, estimate. In some cases if you have memorized some of the square roots, you can estimate where the number would be.
ie.
you know that 
and 
, so you can estimate that the would be between 7 and 8 but closer to 8.
5. <span>Alternatively, reduce your number to its lowest common factors as your first step.</span><span> Finding perfect square factors isn't necessary if you can easily determine a number's prime factors (factors that are also prime numbers).
ie. </span>
=
=
=
Hope this helped!!!
The first two steps work for solving large perfect squares as well.
1. Divide your number into perfect square factors.
2. Take the square roots of your perfect square factors.
3. If your number doesn't factor perfectly, reduce your answer to simplest terms.
4. If needed, estimate. In some cases if you have memorized some of the square roots, you can estimate where the number would be.
ie.
5. <span>Alternatively, reduce your number to its lowest common factors as your first step.</span><span> Finding perfect square factors isn't necessary if you can easily determine a number's prime factors (factors that are also prime numbers).
ie. </span>
=
=
=
Hope this helped!!!