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3 years ago

Express the fraction 11/30 in decmail form

Mathematics

2 answers:

Artemon [7]3 years ago

7 0

0.3667
hope this helped

ella [17]3 years ago

4 0

Answer:

.36666667

Step-by-step explanation:

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The length of an object is measured as 65.8 centimeters what is this measurement in scentific notation

julsineya [31]

Answer:

6.58 x 10^1

Step-by-step explanation:

This is because the exponent 1 means that you have to move the decimal place in 6.58 to the right once which makes the standard form 65.8. And vice versa, if you move the decimal place to the left once in 65.8, then the answer is 6.58 x 10^1.

7 0

3 years ago

Simplify the following algebraic expression: 2 (2x + 3y) + 3 (5 – 2x) +1+y

Gnoma [55]

Answer: -2x+7y+16

Step-by-step explanation:

1. Distribute 2 through the parentheses

4x+6y+3(5-2x)+1+y
4x+6y+15-6x+1+y

2. Collect like terms

-2x+6y+15+1+y
-2x+7y+15+1
-2x+7y+16

3. Solution, -2x+7y+16

5 0

3 years ago

I'm stuck, please help me

Sav [38]

60/48
x100
60/48=1.25
1.25x100
125%

3 0

3 years ago

Read 2 more answers

I’m getting 9.8 not sure what I’m doing wrong

Afina-wow [57]

Answer: 10

Step-by-step explanation:

it says round to nearest 10 your answer was 9.8 so round to 10.

hope this helps :)

7 0

3 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

5 0

3 years ago

Read 2 more answers