All categories

2 years ago

The circumference of a circle is 31.4 inches. What is the circle's diameter? C=31.4 in Use 3.14 for .

2 answers:

8 0

We will use the circumference formula to find the radius and then multiply it by 2 to find the diameter.

C = 2πr
31.4 = (2)(3.14)(r)
31.4 = 6.28r
5 = r

So our radius is 5 in.

We can multiply it by 2 to get the diameter.

5*2 = 10

So the diameter is 10 inches

liubo4ka [24]2 years ago

6 0

49.3
this can be calc for a form

You might be interested in

I've been stuck on this for about 2 hours but it still doesn't make any sense to me, please helpppppppppp

Mariana [72]

I really hope this helps. I’m sure the answer is c:)

5 0

2 years ago

Number 12. Find angle ADE

mr_godi [17]

Answer:

ADE=59º

Step-by-step explanation:

4x+15+13x+7=90

17x+22=90

17x=68

x=4

angle B=angle ADE so we plug in x=4 into 13x+7

13(4)+7=59º

5 0

2 years ago

Read 2 more answers

Which number is a factor of 56 6, 8,11,112?

Lelechka [254]

8 would be the best answer to the question.

3 0

3 years ago

Find the greatest four digit square number by division method

Agata [3.3K]

9999 is largest 4 digit number, and 100^2 is 10000, or 1 greater than the largest 4 digit number. This means that the closest square root of the largest perfect square is most likely 99. So 99^2 (9801)is the largest perfect square of four digits.

7 0

3 years ago

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

3 years ago

The circumference of a circle is 31.4 inches. What is the circle's diameter? C=31.4 in Use 3.14 for ​.

The circumference of a circle is 31.4 inches. What is the circle's diameter? C=31.4 in Use 3.14 for .