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torisob [31]
4 years ago
6

Is the Lcm of a pair of numbers ever equal to one of the numbers

Mathematics
1 answer:
Arlecino [84]4 years ago
8 0
It is a 183 of the sum
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Simplify the expression sin^2x-1/cos(-x)
s344n2d4d5 [400]
Use the Pythagorean identity sin ^{2} x+cos ^{2} x=1
to simplify the numerator.
sin ^{2} x-1=-cos ^{2} x
Now use that fact that
cos(-x)=cos(x) to set up the equivalent fraction:
\frac{sin ^{2}x-1 }{cos(-x)} = \frac{-cos ^{2}x }{cos(x)}
Now reduce between the numerator and denominator to get -cos(x)
4 0
3 years ago
PLEASE HELP !!!! A box of 6 golf balls costs $7.32. At that rate how much will a box of 15 golf balls costs?
vazorg [7]
7.32/6=1.22
1.22*15=18.3
The golf balls will cost $18.30
4 0
3 years ago
Read 2 more answers
HELLP<br> What is the formula for finding the perimeter of a polygon?
Kaylis [27]

Answer:

P=n*s

Step-by-step explanation:

n is the number of sides and s is the length of any one side.

8 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!dgbdgdbhdndcn
bogdanovich [222]
Problem 1)

AC is only perpendicular to EF if angle ADE is 90 degrees

(angle ADE) + (angle DAE) + (angle AED) = 180
(angle ADE) + (44) + (48) = 180
(angle ADE) + 92 = 180
(angle ADE) + 92 - 92 = 180 - 92
angle ADE  = 88

Since angle ADE is actually 88 degrees, we do NOT have a right angle so we do NOT have a right triangle

Triangle AED is acute (all 3 angles are less than 90 degrees)

So because angle ADE is NOT 90 degrees, this means AC is NOT perpendicular to EF

-------------------------------------------------------------

Problem 2)

a) The center is (2,-3) 

The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2

---------------------

b) The radius is 3 and the diameter is 6

From part a), we have (x-2)^2+(y-(-3))^2 = 3^3 matching (x-h)^2 + (y-k)^2 = r^2

where
h = 2
k = -3
r = 3

so, radius = r = 3
diameter = d = 2*r = 2*3 = 6

---------------------

c) The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.

Some points on the circle are

A = (2, 0)
B = (5, -3)
D = (2, -6)
E = (-1, -3)

Note how the distance from the center C to some point on the circle, say point B, is 3 units. In other words segment BC = 3.

6 0
3 years ago
Jason had $32. He spent all the money on buying 4 CDs for $x each and 2 magazines for $y each. If Jason had bought 5 CDs and 2 m
Leni [432]
You can set up two equations from the information given. I will set them up for you:

32 = 4x + 2y
36 = 5x + 2y

Let's solve the first equation to come up with a value for y.

32 = 4x + 2y
32 - 4x = 2y
16 - 2x = y

Now we plug y into the other equation.

36 = 5x + 2(16-2x)
36 = 5x + 32 - 4x
4 = x

Now we have our real x value and we can plug it into the first equation.

32 = 4(4) + 2y
32 = 16 + 2y
16 = 2y
8 = y

Since x = 4 and y = 8, you get the final coordinates of (4,8).

Your answer is the second statement provided above.
3 0
3 years ago
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