All categories

3 years ago

What is the value of x?

Mathematics

2 answers:

wariber [46]3 years ago

4 0

I'm pretty sure the answer is A. 66 degrees. I hope this helps.

Sonja [21]3 years ago

3 0

Answer:

A. $66^{\circ}$ .

Step-by-step explanation:

We have been given an image of two angles. We are asked to find the value of x.

Upon looking at our given image we can see that the measure of one angle is 110 degrees and measure of second angle is x.

We can also see that both angle add up-to 176 degrees, so we can set an equation as:

$x+110^{\circ}=176^{\circ}$

Let us solve for x.

$x+110^{\circ}-110^{\circ}=176^{\circ}-110^{\circ}$

$x=66^{\circ}$

Therefore, measure of x is 66 degrees and option A is the correct choice.

You might be interested in

Find the common ratio an=4n-2

S_A_V [24]

The answer is 8 thank we'll come

8 0

3 years ago

It costs $2.00 per hour to park in the parking deck. Ben parks for 3 hours. The automated machine used for payment will only acc

solmaris [256]

Answer:

the correct answer is 24 quarters

Step-by-step explanation:

Since Ben parks for 3 hours and one hours costs $2

Therefore 3 hours = $2.00 × 3 hours = $6.00

Next, note that 1 quarter = 25 cents (same as One-quarter of a dollar)

∴ 1 quarter = 1/4 dollar

= 1 quarter = 0.25 dollars.

$0.25 = 1 quarter

∴ $6 = (1/0.25) × 6 = (6 ÷ 0.25) = 24 quarters

5 0

3 years ago

Read 2 more answers

Suppose you want to prove a theorem of the form p → (q ∨ r). Prove that this is equivalent to showing that (p ∧ ¬q) → r.

tino4ka555 [31]

You "distributed" the negation inside the parenthesis. Let's focus on the $\lnot (p\wedge \lnot q)$ part.

We can distribute the negation inside the parenthesis by negating every term, and switching and with or, and vice versa. So, you have

$\lnot (p\wedge \lnot q) \equiv (\lnot p) (\lnot \wedge) (\lnot \lnot q)$

Of course, writing $\lnot \wedge$ is improper, I was just stressing the fact that we distributed the negation to every term in the parenthesis. So, since a double negation cancels out, you're left with

$\lnot (p\wedge \lnot q) \equiv \lnot p \lor q$

which of course implies that

$\lnot (p\wedge \lnot q) \lor q \equiv (\lnot p \lor q) \lor q$

Edit: I actually derived the expression in the opposite order, but since they are equivalent, it doesn't really matters where you start from and where you get to. Anyway, if you actually want to derive $\lnot (p \wedge \lnot q) \lor r$ from $(\lnot p \lor q)$ , you simply have to negate the first parenthesis and distribute the negation as discussed.