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Simora [160]
3 years ago
12

Justin is getting a salary raise of $5,000. He wants to put this money in a relatively safe investment. Which investment has the

least risk?
Mathematics
2 answers:
malfutka [58]3 years ago
6 0
The type of investment that has the leats risk is the one called Saving bonds because it is backed by the government, and they’re guaranteed not to lose principal. T<span>hey’re tax-free on both the state and local levels.</span>
Ivanshal [37]3 years ago
6 0

Answer:

The answer for PLATO USERS would be D: US treasury bonds

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I don’t know how to solve this problem,
xxTIMURxx [149]

Answer:

380/week

Step-by-step explanation:

all u do is 1520 divide by 4 (bc he makes 1520 in 4 weeks) and that would equal 380 per week.

hoped that helped:P

6 0
2 years ago
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Write the equation: 5 more than 3 times a number is 20
zlopas [31]
5+3n=20



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3 0
3 years ago
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Another easy question need fast please
Tresset [83]

Answer:

30.25

Step-by-step explanation:

All angles of a line must add up to 180. Since we already know that one angle is 90 degrees, we know that the other angles should add up to 90 degrees in order for all of the angles to add up to 180 degrees:

(3x-7)+(x+8)=90

4x+1=90

4x=89

x=22.25

22.25+8= 30.25

3 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!
lakkis [162]

Answer:

false i think? and true

Step-by-step explanation:


8 0
3 years ago
Solve using long division <br> Please
madreJ [45]

1. Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}

Steps:

\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}

\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}

\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}

\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}

\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}

2. Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}

Steps:

\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}

\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}

\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

4 0
3 years ago
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