Answer:
<h2>
46</h2>
Step-by-step explanation:
x - age of a son three years ago
3x - age of a father three years ago
x + 3 - age of the son now
3x + 3 - age of the father now
x + 3 + 5 - age of the son in five years time
3x + 3 + 5 - age of the father in five years time
in five years time, the father will be twice as old as his son, so:
3x + 3 + 5 = 2(x + 3 + 5)
3x + 8 = 2x + 16
3x - 2x = 16 - 8
x = 8
x + 3 + 4 - age of the son in four years time
8 + 3 + 4 = 15
3x + 3 + 4 - age of the father in four years time
3×8 + 3 + 4 = 31
the sum of their ages in four years time:
15 + 31 = 46
3.
a. 380 ÷ 38 = 10
b. 190 ÷ 38 = 5
c. 570 ÷ 38 = 15
d. use 10 times 38 = 380, 190 is half of 380 so half of 10 is 5, 570 is 380 + 190 so 10 + 5
4.
a. 670 ÷ 67 = 10
b. 603 ÷ 67 = 9
c. 737 ÷ 67 = 11
d. use 10 times 67 = 670, 603 is 670 - 67 so 10 - 1 = 9, 737 is 670 + 67 so 10 + 1 = 11
Challenge:
1062 - 279 = 783

783 - 261 = 522
522 ÷ 15 = 34 remainder 12
So she put 34 books in each box
Since this is a right triangle, you can use the main trig functions sin, cos, and tan. We must use sin for this problem because sin= opp/hyp. Plug in the numbers to this function. Sin (53) = a/25. Thus when you cross multiply, you get a= sin (53) x 25. When you plug it into a calculator the answer should come out to 19.97
Comparing x-1 with x-a then x=1
1^3+p*1^2-1-2=0
1+2p-3=0
2p=3-1
P=2/2
P=1
:.p=1