All categories

3 years ago

Question: (Graph photo attached)

Mathematics

1 answer:

Artist 52 [7]3 years ago

8 0

Answer:

The line plot depicted shows, number of books read by 15 students .

Books read Number of Students

0 0

1 1

2 2

3 2

4 3

5 1

6 2

7 3

8 1

9 0

Number of students who read more than 3 books

= 3 + 1 +2+3+1+0

= 10 students

Option C

You might be interested in

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

Consider the vitamin capsule below.

shusha [124]

Answer:

We have a cylinder and two semispheres.

The volume of a cylinder is equal to:

Vc =h*pi*r^2

where h is the height, r is the radius, and pi = 3.14

We know that the diameter is d = 8.4 mm, and the radius is half of that:

r = 8.4mm/2 = 4.2mm

Then the volume of the cylinder is:

Vc = 15.2mm*3.14*(4.2mm)^2 = 841.9 mm^3

The volume of a sphere is:

Vs = (3/4)*pi*r^3

The radius of the sphere is the same as the radius of the cylinder, and for a semisphere, we have half of the volume written above,

Vss = (3/8)*3.14*(4.2mm)^2 = 87.2mm^3

and we have two of those, so the total volume is:

Vt = 841.9 mm^3 + 2*87.2mm^3 = 1016.3 mm^3

The surface area of the figure is equal to the curved surface of the cylinder plus the surface of the two semispheres.

The curved surface of the cylinder is:

Sc = 2*pi*r*h = 2*3.14*4.2mm*15.2mm = 400.9 mm^2

The surface of a sphere is:

Ss = 4*pi*r^2

and for each semisphere, we can find the surface by dividing the previous equation by two, but we have two semispheres, so we can jump a step and think the two semispheres as only one sphere.

Ss = 4*3.14*(4.2mm)^2 = 221.6mm^2

The total surface is St = 221.6mm^2 + 400.9 mm^2 = 622.5 mm^2

7 0

4 years ago

Select the correct answer.

charle [14.2K]

Answer: C

Step-by-step explanation:

$4^{-11/3 -(-2/3)=4^{-11/3 + 2/3}=4^{-3}=1/64$