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ankoles [38]
3 years ago
5

Factorise (x+y)^3- (x^3+y^3) plzzz answer ​

Mathematics
1 answer:
lilavasa [31]3 years ago
5 0

Answer:

\huge \boxed{ \boxed{ \tt 2xy(x + y)}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • factoring
  • PEMDAS
<h3>tips and formulas:</h3>
  • (a+b)³=a³+3a²b+3ab²+b³
  • a³+b³=(a+b)(a²-ab+b²)
<h3>let's solve:</h3>
  1. \sf \: use \: 2nd \: formula \: to \: simplify :  \\  \sf(x + y {)}^{3}  - (x + y)( {x}^{2}  - xy +  {y}^{2} )
  2. \sf factor \: out \: (x + y) :  \\ (x + y )\{(x + y)^{2} - ( {x}^{2}  - xy +  {y}^{2}  \}
  3. \sf simplify :  \\ (x + y {)} \{ {x}^{2}  + 2xy +  {y}^{2}  -  {x}^{2}  + xy -  {y}^{2}  \}
  4. \sf collect \: and \: combine \: like \: terms :  \\ (x + y) \{2xy \}
  5. \sf \: rewrite : \\  2xy(x + y)

and

we are done

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myrzilka [38]

In this example, y is equal to 8.

In order to find this, first note that the two x value expressions create a straight line. That means when we add them together they will equal 180. this will give us a value for x.

x + 10 + 10x - 61 = 180

11x - 51 = 180

11x = 231

x = 21

Now that we have the value of x, we can do the same for the straight line created by the x + 10 angle and the 18y + 5 angle.

x + 10 + 18y + 5 = 180

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Answer:

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