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ankoles [38]
3 years ago
5

Factorise (x+y)^3- (x^3+y^3) plzzz answer ​

Mathematics
1 answer:
lilavasa [31]3 years ago
5 0

Answer:

\huge \boxed{ \boxed{ \tt 2xy(x + y)}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • factoring
  • PEMDAS
<h3>tips and formulas:</h3>
  • (a+b)³=a³+3a²b+3ab²+b³
  • a³+b³=(a+b)(a²-ab+b²)
<h3>let's solve:</h3>
  1. \sf \: use \: 2nd \: formula \: to \: simplify :  \\  \sf(x + y {)}^{3}  - (x + y)( {x}^{2}  - xy +  {y}^{2} )
  2. \sf factor \: out \: (x + y) :  \\ (x + y )\{(x + y)^{2} - ( {x}^{2}  - xy +  {y}^{2}  \}
  3. \sf simplify :  \\ (x + y {)} \{ {x}^{2}  + 2xy +  {y}^{2}  -  {x}^{2}  + xy -  {y}^{2}  \}
  4. \sf collect \: and \: combine \: like \: terms :  \\ (x + y) \{2xy \}
  5. \sf \: rewrite : \\  2xy(x + y)

and

we are done

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please answer the question on the screenshot below, also please explain to me how you got your answer.
frutty [35]

QUESTION 1

The given functions are;

f(x)=5x^2-2x and g(x)=5x^2+x-4

(f+g)(x)=f(x)+g(x)

(f+g)(x)=5x^2-2x+3x^2+x-4

We regroup like terms to obtain;

(f+g)(x)=5x^2+3x^2-2x+x-4

This simplifies to;

(f+g)(x)=8x^2-x-4

The correct answer is A.

QUESTION 2

The given functions are;

f(x)=3x^2+5 and g(x)=x-2.

(fg)(x)=(f(x))(g(x))

This implies that;

(fg)(x)=(3x^2+5)(x-2)

\Rightarrow (fg)(x)=3x^3-6x^2+5x-10

The correct answer is B.

QUESTION 3

The given functions are

f(x)=3x^2+10x-8 and g(x)=3x^2-2x.

(\frac{f}{g})(x)=\frac{f(x)}{g(x)}

(\frac{f}{g})(x)=\frac{3x^2+10x-8}{3x^2-2x},x\ne0,\frac{2}{3}

We factor to obtain;

(\frac{f}{g})(x)=\frac{(x+4)(3x-2)}{x(3x-2)},x\ne0,\frac{2}{3}

We cancel the common factors to obtain;

(\frac{f}{g})(x)=\frac{x+4}{x},x\ne0,\frac{2}{3}

The correct answer is A.

5 0
3 years ago
What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the la
olga55 [171]
Let's say the first number is "a"
the next consecutive can just be "a+1" and  the next, you guessed it, "a+2"
the two smaller ones are a and a+1, the larger one is a+2

now, the product of "a" and "a+1" equals 5 times "a+2" but less by 5

thus   a(a + 1) = 5(a + 2) - 5   <----- solve for "a"
7 0
2 years ago
What is the constant term in the expression 5x^2+7x+4?
Doss [256]

Answer: 4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find four consecutive integers with a sum of 106.
grandymaker [24]
4 consecutive integers...
x, x + 1, x + 2, x + 3

x + x + 1 + x + 2 + x + 3 = 106
4x + 6 = 106
4x = 106 - 6
4x = 100
x = 100/4
x = 25

x + 1 = 25 + 1 = 26
x + 2 = 25 + 2 = 27
x + 3 = 25 + 3 = 28

ur 4 integers are : 25,26,27,28
6 0
2 years ago
PLEASE HELP THANKS YOU
kondaur [170]
U must find the median, the range, and the mode. And that is your answer
8 0
2 years ago
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