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3 years ago

Factorise (x+y)^3- (x^3+y^3) plzzz answer

Mathematics

1 answer:

lilavasa [31]3 years ago

5 0

Answer:

$\huge \boxed{ \boxed{ \tt 2xy(x + y)}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

factoring
PEMDAS

<h3>tips and formulas:</h3>

(a+b)³=a³+3a²b+3ab²+b³
a³+b³=(a+b)(a²-ab+b²)

<h3>let's solve:</h3>

$\sf \: use \: 2nd \: formula \: to \: simplify : \\ \sf(x + y {)}^{3} - (x + y)( {x}^{2} - xy + {y}^{2} )$
$\sf factor \: out \: (x + y) : \\ (x + y )\{(x + y)^{2} - ( {x}^{2} - xy + {y}^{2} \}$
$\sf simplify : \\ (x + y {)} \{ {x}^{2} + 2xy + {y}^{2} - {x}^{2} + xy - {y}^{2} \}$
$\sf collect \: and \: combine \: like \: terms : \\ (x + y) \{2xy \}$
$\sf \: rewrite : \\ 2xy(x + y)$

and

we are done

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3 years ago

Factorise (x+y)^3- (x^3+y^3) plzzz answer ​

Factorise (x+y)^3- (x^3+y^3) plzzz answer