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3 years ago

5

Factorise (x+y)^3- (x^3+y^3) plzzz answer

1 answer:

lilavasa [31]3 years ago

5 0

Answer:

$\huge \boxed{ \boxed{ \tt 2xy(x + y)}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

factoring
PEMDAS

<h3>tips and formulas:</h3>

(a+b)³=a³+3a²b+3ab²+b³
a³+b³=(a+b)(a²-ab+b²)

<h3>let's solve:</h3>

$\sf \: use \: 2nd \: formula \: to \: simplify : \\ \sf(x + y {)}^{3} - (x + y)( {x}^{2} - xy + {y}^{2} )$
$\sf factor \: out \: (x + y) : \\ (x + y )\{(x + y)^{2} - ( {x}^{2} - xy + {y}^{2} \}$
$\sf simplify : \\ (x + y {)} \{ {x}^{2} + 2xy + {y}^{2} - {x}^{2} + xy - {y}^{2} \}$
$\sf collect \: and \: combine \: like \: terms : \\ (x + y) \{2xy \}$
$\sf \: rewrite : \\ 2xy(x + y)$

and

we are done

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please answer the question on the screenshot below, also please explain to me how you got your answer.

frutty [35]

QUESTION 1

The given functions are;

$f(x)=5x^2-2x$ and $g(x)=5x^2+x-4$

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=5x^2-2x+3x^2+x-4$

We regroup like terms to obtain;

$(f+g)(x)=5x^2+3x^2-2x+x-4$

This simplifies to;

$(f+g)(x)=8x^2-x-4$

The correct answer is A.

QUESTION 2

The given functions are;

$f(x)=3x^2+5$ and $g(x)=x-2$ .

$(fg)(x)=(f(x))(g(x))$

This implies that;

$(fg)(x)=(3x^2+5)(x-2)$

$\Rightarrow (fg)(x)=3x^3-6x^2+5x-10$

The correct answer is B.

QUESTION 3

The given functions are

$f(x)=3x^2+10x-8$ and $g(x)=3x^2-2x$ .

$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}$

$(\frac{f}{g})(x)=\frac{3x^2+10x-8}{3x^2-2x},x\ne0,\frac{2}{3}$

We factor to obtain;

$(\frac{f}{g})(x)=\frac{(x+4)(3x-2)}{x(3x-2)},x\ne0,\frac{2}{3}$

We cancel the common factors to obtain;

$(\frac{f}{g})(x)=\frac{x+4}{x},x\ne0,\frac{2}{3}$

The correct answer is A.

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3 years ago

What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the la

olga55 [171]

Let's say the first number is "a"
the next consecutive can just be "a+1" and the next, you guessed it, "a+2"
the two smaller ones are a and a+1, the larger one is a+2

now, the product of "a" and "a+1" equals 5 times "a+2" but less by 5

thus a(a + 1) = 5(a + 2) - 5 <----- solve for "a"

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2 years ago

What is the constant term in the expression 5x^2+7x+4?

Doss [256]

Answer: 4

Step-by-step explanation:

6 0

3 years ago

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Find four consecutive integers with a sum of 106.

grandymaker [24]

4 consecutive integers...
x, x + 1, x + 2, x + 3

x + x + 1 + x + 2 + x + 3 = 106
4x + 6 = 106
4x = 106 - 6
4x = 100
x = 100/4
x = 25

x + 1 = 25 + 1 = 26
x + 2 = 25 + 2 = 27
x + 3 = 25 + 3 = 28

ur 4 integers are : 25,26,27,28

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2 years ago

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kondaur [170]

U must find the median, the range, and the mode. And that is your answer

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2 years ago

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