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Archy [21]
3 years ago
14

ana wants to earn 88 percent in her chemistry class she has one quiz left to take on the first 5 quizzes she received a 74 perce

nt a 92 percent and a 83 percent and 100 percent what must she score on the 6th quiz to get the 88 she wants?
Mathematics
1 answer:
Alinara [238K]3 years ago
4 0

Answer: 91

Step-by-step explanation: I assume you had a typo and mean what did Ana need on the 5th quiz since you only listed 4 quiz scores.

(74 + 92 + 83 + 100 + x)/5 = 88

(349 + x)/5 = 88

((349 +x)/5) x 5 = 88 x 5

349 + x = 440

x = 440-349

x  = 91

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3 years ago
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What type of triangle has side lengths 9, 10, and √130? A. obtuse B. not a triangle C. acute D. right
EastWind [94]

Answer: Option C.

Step-by-step explanation:

The lengths of our triangle are:

9, 10 and √130.

If the triangle is a triangle rectangle, by the Pitagoream's theorem we have:

A^2 + B^2 = H^2

in this case H is the larger side, this must be √130.

then:

A and B must be 9 and 10.

9^2 + 10^2 = (√130)^2

81 + 100 = 130

This is false, so this is NOT a triangle rectangle, the hypotenuse is shorter than it should be.

Now, we have some kind of rule:

 if A^2 + B^2 = H^2 then we have one angle of 90° and two smaller ones. (triangle rectangle)

 if A^2 + B^2 > H^2 then all the angles are smaller than 90°, this is an acute triangle.

 if A^2 + B^2 < H^2 then we have one angle larger than 90°, this is an obtuse angle.

(H is always the larger side, A and B are the two shorter ones).

In this case:

81 + 100 > 130

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3 0
2 years ago
What is the quotient in simplified form ? Need help please
Gre4nikov [31]

Answer:

  -\dfrac{4a^{12}b^8}{5}

Step-by-step explanation:

The applicable rules of exponents are ...

  \dfrac{1}{a^{-b}}=a^b\\\\a^ba^c=a^{b+c}

Your ratio simplifies to ...

  \dfrac{-8a^8b^{-2}}{10a^{-4}b^{-10}}=-\dfrac{4}{5}a^{8-(-4)}b^{-2-(-10)}\\\\=-\dfrac{4a^{12}b^8}{5}

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Please note that simplifying the constants, -8/10 to -4/5, eliminates half the answer choices. Since exponents are only multiplied when a power is raised to a power, you can pretty much eliminate the second choice as being unreasonable. ((a^b)^c = a^(bc))

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3 years ago
An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

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(b)Flight Direction of Y

Using Law of Sines

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The direction of flight Y to the nearest degree is 39 degrees.

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