OM=18, so OQ=QM=18/2=9.
 Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
        
             
        
        
        
In one third you would need 12 one thirds to make a whole sixth
        
                    
             
        
        
        
P(1) = P(0) [exp (rt)]
9,800 = 10,000 (0.98)^1
r = loge<span> (0.98)  = ln (0.98) = -0.0202
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<span>P(t) = P(0)[exp(-0.0202t)]</span>