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Wittaler [7]
3 years ago
12

In addition to the trigonometric ratios, what other methods can be used to solve a right triangle? Give situations for when you

might want to use them

Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0
Consider the right triangle shown below.
We shall discuss two methods for solving the right triangle.

Method 1. Use of trigonometric ratios
To use trigonometric ratios requires that either m∠A or m∠B is known and that one of the sides a, b, or c is known.
Example:
Assume that m∠A is known, then m∠B = 90° - m∠A.
Also, assume that b is known.
By definition,
tan A = a/b  => a = b*tan A
cos A = b/c  => c = b/cos A, or
sin A = a/c  =>  c = a/sin A 

Method 2. Algebraic method
When neither m∠A nor m∠B is known, then it is necessary to know the values of two sides: (a and b), (a and c), or (b and c).
The Pythagorean theorem states that
a² + b² = c²
(a) If a and b are known, then
c = √(a² + b²)
(b) If a and c are known, then
b = √(c² - a² )
(c) If b and c are known, then
a = √(c² - b²)

Once all sides are known, trigonometric ratios can be used t determine m∠A and m∠B.
Example:
Because a and c are known,
sin A = a/c
A = sin⁻¹ (a/c), which can be determined from the calculator.

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ziro4ka [17]
We see it is the y terms squared so it opens left or right

in form
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if p>0, then it opens to the right and dirextix is to the left of vertex
if p<0, then it opens to the left and directix is tothe right of vertex


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3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
pashok25 [27]

Answer:

Graph A → y=√x.

Graph B → y=(√x) - 1.

Graph C → y=√(x-1).

Graph D → y= -√x.

Graph E → y= -√(x-1)

Step-by-step explanation:

The graph 'A' intercepts the y-axis at (0, 0). Therefore it belongs to the function y=√x.

The graph 'D' is exactly the same graph 'A' but reflected across the x-axis. Therefore, it belongs to the function y=-√x.

The function 'C' is exactly the same function y=√x but translated one unit to the right, therefore, the solution function is y=√(x-1)

The graph 'E' is exactly the same graph 'C' but reflected across the x-axis, therefore the function is: y= -√(x-1)

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