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IceJOKER [234]
3 years ago
10

Evaluate sin(Arcos(-9/√145)).

Mathematics
2 answers:
tino4ka555 [31]3 years ago
8 0

Use the fact that \sin x = \sqrt{1-\cos^2 x} to solve it.

\sin(\arccos(-\frac{9}{\sqrt{145}}))=\sqrt{1-\cos^2(\arccos(-\frac{9}{\sqrt{145}}))} =\\= \sqrt{1-(-\frac{9}{\sqrt{145}})^2}=\frac{8}{\sqrt{145}}

makkiz [27]3 years ago
7 0

Answer:

a

Step-by-step explanation:

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