Answer:
Some of the major biogeochemical cycles are as follows: (1) Water Cycle or Hydrologic Cycle (2) Carbon-Cycle (3) Nitrogen Cycle (4) Oxygen Cycle. The producers of an ecosystem take up several basic inorganic nutrients from their non-living environment.
Explanation:
Aluminum can be oxidized by
and 
<h3>What is oxidizing?</h3>
Some of the metal corrodes (or oxidizes) and forms the corresponding metal oxide on the surface as a result of a chemical reaction between the metal surface and the oxygen in the air. The corrosion products that occur in some metals, like steel, are highly apparent and loose.
According to reactivity series (The array of metals in the descending order of their reactivities is referred to as the metals' reactivity series. It is sometimes referred to as the metals in the activity series.)
Lithium and calcium ions are more reactive than aluminum ion and they are less electronegative.
Since silver and tin are more electronegative than aluminum so, they cannot oxidize aluminum.
∴
and
ions can oxidize aluminum.
Learn more about electronegativity here brainly.com/question/16446391
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Answer:
The answer is
<h3>6000 N/m² or 6000 Pa</h3>
Explanation:
The pressure exerted by an object given the force of the object and the area can be found by using the formula

where
P is the pressure
f is the force
a is the area
From the question
f = 2400 N
a = 0.4 m²
So we have

We have the final answer as
<h3>6000 N/m² or 6000 Pa</h3>
Hope this helps you
The standard plate count is used to determine the total number of bacteria present in a specified amount of milk, usually a milliliter (mL). This is used for the grading of milk. The coliform plate count is widely used to determine the total number of coliforms present in one mL of milk sample.
132 g of C , 22 g of H , 176 g of O
132 + 22 + 176 => 330 g <span>of the substance
</span>Now convert the masses in <span>moles :
</span>
C = 12.0 u H = 1.0 u O = 16.0 u
C = 132 / 12.0 => 11 moles
H = 22 / 1.0 => 22 moles
O = 176 / 16.0 => 11 moles
Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
</span>
C = 11 / 11 => 1
H = 22 / 11 => 2
O = 11 / 11 => 1
formula empirically <span>is : CH</span>₂O
hope this helps!