Determine the number of bonding electrons and the number of nonbonding electrons in the structure of OF2. Enter the number of bo
nding electrons followed by the number of nonbonding electrons in the dot structure of this molecule separated by a comma (e.g., 1,2).
2 answers:
Answer:
(4,20)
Explanation:
Oxygen di-fluoride or OF2 is a polar molecule, formed through the covalent bonding between one Oxygen and two Fluorine atoms.
Oxygen has atomic no. 8 and its electronic configuration is as below:
- 1s^2, 2s^2, 2p^4
Oxygen has 4 electrons in the valence shell. It has the ability to share two electrons with other atoms through covalent bond and get stable.
The atomic number of Fluorine is 7, and its electronic configuration is as:
- 1s^2, 2s^2, 2p^5
So, Fluorine atom has the capacity to accept 1 electron to form 1 covalent bond or in the formation of the F- ion.
The structure of OF2 is a bent structure with O atom sandwiched by two fluorine atoms like F-O-F. So there are two electrons on oxygen atom that are taking part in the formation of covalent bond with each Fluorine atom (Please dot structure in figure).
Now we can easily calculate no of bonding and non-bonding electrons.
- No. of bonding electrons = 4 (two from oxygen and two from fluorine atoms each)
- No. of non-bonding electrons= 20 (6+6 from two Fluorine atoms and 6 from Oxygen atom)
Hope it helps! :)
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