OF2-
O has 6 electrons in its outer shell and F has 7 electrons in its outer shell
<h2>Further Explanation
</h2>
Therefore, you want to account for a complete of 20 electrons in
structure (7 + 7 + 6 = 20)
therefore draw linear first. F ---- O ----- F
Two bonds make sure of 4 electrons now you have got to feature 16 others.
Therefore 3 free pairs on each F and a pair of free pairs on O.
If you check the formal charges, all atoms are neutral
F will have 3 electron pairs + 1 bond = 7 electrons (bond = 1/2 electron for the formal charge distribution) therefore both F's are neutral
Now look O: it must have 6. it's two negatron pairs and a pair of bonds = 4 electrons and a pair of bonds = 1 electron each = 2 electrons from the bond = 6 total electrons for the precise formal charge # should have. there's no need for double bonds during this case because there aren't any costs to separate.
Now if you observe # domains around O you'll see if you enter a free pair that has sp3 hybridization (4 domains) therefore a tetrahedron that has 2 electron pairs and a pair of bonds .. because there are two electron pairs, repulse single pairs/pairs the bond is so high that it expels both fluorine and forms a bent structure, noticeably like H2O.
Learn More
Electrons Bond brainly.com/question/11486787
Outer Shell brainly.com/question/11486787
Details
Grade: College
Subject: Chemistry
Keyword: electron, bond, shell