Well theoretically speaking you could but that would take a long time and 15 and 30 have a common factor of 5 and 15. So I think for this one you can't since there are two common factors.
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Answer:
Triangles ABE and CDE are congruent by AAS.
Step-by-step explanation:
AB ≅ DC (Opposite sides of a parallelogram are congruent.
m < AEB = m < DEC (Vertical angles).
m < ABE = m < EDC ( Alternate Interior angles).
So triangles ABE and CDE are congruent by AAS.
Answer:
6:11
Step-by-step explanation:
It would be the first answer. Bubble. I don't know what you call it. But yeah, it's the first one.
(cos Ф -cos Ф)² + (cos Ф + cos Ф)²
Firstly: (cos Ф -cos Ф)² = 0² = 0
Secondly :(cos Ф + cos Ф)² = (2cos Ф)². = 4. (cos Ф)² = 4cos² Ф
Mind you when you raise a cosine (or sin or tan...) to the n power, the n power should affect the cosine only and NOT the angle Ф
