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Vedmedyk [2.9K]
3 years ago
13

Kelly subtracted 2.3 from 20 and got 17.7. explain why this answer is reasonable

Mathematics
2 answers:
nignag [31]3 years ago
7 0
The correct answer to this is that 2.3 -20=-17.7 the answer is resonable because if you go on a number line then you would see that if you start a 2.3 and subtract 20 spaces you get to ----17.7
netineya [11]3 years ago
3 0
If 20-2.3=17.7, then if you add 17.7 to 2.3. it equals 20 which is called the communicative property because whatever you add or subtract, the answer is the same
17.7+2.3=2.3+17.7
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An amusement park would like to determine if they want to add in a new roller coaster. In order to decide whether or not they sh
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Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given by:

n = 600, \pi = \frac{400}{600} = 0.6667

Hence, the bounds of the interval are given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 - 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6350

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 + 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6984

The 90% confidence interval is given by: (0.6350, 0.6984).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

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Write this number in word form. 284,028
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Step-by-step explanation:

7. I believe it's independent because it makes sense and if it was dependent it wouldn't make senses.

8.For T you have 2 (Ts) so that give you a 2/8= 25% so you would basically make those Ts disappear and focus on 1 out of 6 and you'd get a 16.67% chance

9. 14.2857%

10. I don't understand ;-; am I suppose to multiply or see the chance if % it would get

I'm sorry;-;

5 0
2 years ago
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