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3 years ago

Can someone please help, ty!! Will mark brainliest!

Mathematics

2 answers:

rewona [7]3 years ago

6 0

Answer:

Step-by-step explanation:

55+82+missing angle=180 degree(sum of interior angle of atriangle is 180 degree)

137+missing angle=180

missing angle=180-137

missing angle=43 degree

therefore ur answer is 43 degree.

PolarNik [594]3 years ago

5 0

The sum of the interior angles of a triangle is 180 degrees. Therefore, if we add up all of these angles, they will equal 180.

82 + 55 + x = 180

137 + x = 180

x = 43 degrees

Hope this helps!! :)

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I need some help to find the equations for the questions. please help asap.

Dmitry [639]

5) Lets use x for the unknown middle side. Since all the sides have to equal to perimeter, we can set everything equal 43.

(x-3)+x+(2x-2)=43

That would be your equation.

6) Knowing what we know from the previous problem, we can set the equation to 27.

(x-3)+x+4(x-3)=27 (we can plug in x-3 to represent the first side)

7) Since all the sides have to equal to perimeter, we can set everything equal 25.

a=2b-2

c=b+3

(2b-2)+b+(b+3)=25

7 0

3 years ago

A production line operates with a mean filling weight of 16 ounces per container. Overfilling or underfilling presents a serious

Dominik [7]

Answer:

Part1) $z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191$

$p_v =2*P(Z>2.191)=0.0284$

Readjustment is needed

Part 2) $z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232$

$z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232$

$p_v =2*P(Z$

No readjustment is needed

Step-by-step explanation:

Data given and notation

Part 1

$\bar X=16.32$ represent the sample mean

$\sigma=0.8$ represent the population standard deviation

$n=30$ sample size

$\mu_o =16$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a two tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu =16$

Alternative hypothesis : $\mu \neq 16$

Compute the test statistic

The statistic for this case is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191$

Give the appropriate conclusion for the test

Since is a two tailed test the p value would be:

$p_v =2*P(Z>2.191)=0.0284$

Using the value of $\alpha =0.05$ we see that $pv$ and we have enough evidence to reject the null hypothesis.

Readjustment is needed

The rejection zone is given by:

$(-\infty ;-1.96) , (1.96;\infty)$

Part 2

$\bar X=15.82$ represent the sample mean

We can replace in formula (1) the info given like this:

$z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232$

Give the appropriate conclusion for the test

Since is a two tailed test the p value would be:

$p_v =2*P(Z$

Using the value of $\alpha =0.05$ we see that $pv>\alpha$ and we have enough evidence to FAIL to reject the null hypothesis.

No readjustment is needed

The rejection zone is given by:

$(-\infty ;-1.96) , (1.96;\infty)$

What action would you recommend ?

Review the procedure.

Do you reach the same conclusion ?

No we got different conclusions

5 0

4 years ago

Will mark brainliest answer!! 50 points!! pls help!!

Afina-wow [57]

Answer:

1. Ben

Let the number of days be x.

Let the total no. of shares be y

$No.\ of\ shares\ on\ Day\ 0=2\\No.\ of\ shares\ on\ Day\ 1\ = 2*3\\No.\ of\ Shares\ on\ Day\ 2\ =\ 2*3*3\\No.\ of\ Shares\ on\ Day\ 3\ = 2*3*3*3\\No.\ of\ Shares\ on\ Day\ x\ =2*3^x\\As\ Total\ no.\ of\ shares\ = y\\y=2*3^x$

2. Carter

Let the no. of days be x

Let the total no. of shares be y

$No.\ of\ shares\ on\ Day\ 0=10\\No.\ of\ shares\ on\ Day\ 1\ = 10*2\\No.\ of\ Shares\ on\ Day\ 2\ =\ 10*2*2\\No.\ of\ Shares\ on\ Day\ 3\ = 10*2*2*2\\No.\ of\ Shares\ on\ Day\ x\ =10*2^x\\f(y)=10*2^x$