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VMariaS [17]
3 years ago
6

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. If f(X)=25-x^2 and

g(X)=x+5, what is (f/g)(x)? Write your answer in simplest form. When f(X)=25-x^2 and g(X)=x+5, (f/g)(x) .
Mathematics
2 answers:
Licemer1 [7]3 years ago
8 0

f(x)=25-x^2\\\\g(x)=x+5\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}=\dfrac{25-x^2}{x+5}=\dfrac{5^2-x^2}{x+5}=\dfrac{(5-x)(5+x)}{5+x}=5-x\\\\for\ x\neq-5

Arada [10]3 years ago
6 0

Answer: -x+5

Step-by-step explanation:

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Imagine you have some workers and some handheld computers that you can use to take inventory at a warehouse. There are diminishi
Svet_ta [14]

Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

  • 1 computer : 1 worker : inventory 150 items per hour
  • 1 computer : 2 workers : inventory 200 items per hour
  • 1 computer : 3 workers : inventory 220 items per hour
  • 1 computer : 4+ workers : fewer than 235 items per hour
  • Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

-One computer used, but the number of users is varied to inventory a specified number of items.

-The variable production factor is the number of workers assigned per one computer.

#The cost of inventorying a single item by one worker is:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

4 0
3 years ago
Slove : 28/36 = 14/y
Dafna1 [17]

Answer:

y = 18

Step-by-step explanation:

<h3><u>i</u><u>)</u><u> </u><u>redu</u><u>ce</u><u> the</u><u> fraction</u><u> </u><u>with</u><u> </u><u>4</u></h3>

\frac{28}{36}  =  \frac{14}{y}

\frac{28 \div 4}{36 \div 4}  =  \frac{14}{y}

\frac{7}{9}  =  \frac{14}{y}

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\frac{7}{9}  =  \frac{14}{y}

7y = 14 \times 9

7y = 126

<h3>iii) <u>divi</u><u>de</u><u> both</u><u> sides</u><u> of</u><u> the</u><u> equation</u><u> </u><u>by</u><u> </u><u>7</u></h3>

<u>\frac{7y}{7}  =   \frac{126}{7}</u>

<u>y = 18</u>

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Answer:

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