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Thepotemich [5.8K]
3 years ago
7

What is the slope of the line shown below.

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0

slope = (y2-y1)/(x2-x1)

(2,4)   (4,8)

 m= (8-4)/(4-2)

m = 4/2

m=2

Answer: 2

Semenov [28]3 years ago
6 0

(2, 4) (4, 8)

you can sue the formula

y2 - y1            8 - 4                4

---------    =  -------------  =  ------------- = 4/2 = 2

x2 - x1           4 -2                 2

or there's an intuitive way to get it

(2, 4) (4, 8)

look at the y's   4 and 8  whats the space between them ?  4

looks at the x's  2 and 4  whats the space between them ?  2

so its 4/2 or 2

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Step-by-step explanation:

use pythagorean theorem. sqrt(14^2+48^2)=50

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Pls help these are my teachers instructions
Yanka [14]

The mistake he did, was in calculating powers, when 12 is taken to numerator it becomes -12 and 6-12 is -6 and not 6 so power of x should be -6 i.e x^-6 and not x^6

So, the correct answer is =\frac{27}{4x^{6}y^{8}}

Step-by-step explanation:

We need to simplify:

\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

Solving:

\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

Multiplying power with the terms inside the bracket.

=\frac{4(3^3x^6y^{12})}{2^4x^{12}y^{20}}\\=\frac{4(27x^6y^{12})}{16x^{12}y^{20}}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}

Now combining powers of same variable i.e if \frac{x^a}{x^b}=x^{a-b}

Solving:

=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{108x^{-6}y^{-8}}{16}\\Divide\,\,by\,\,4:\\=\frac{27x^{-6}y^{-8}}{4}

The exponent rule says: if x^{-1} \,\,then\,\, \frac{1}{x}

=\frac{27}{4x^{6}y^{8}}

The mistake he did, was in calculating powers, when 12 is taken to numerator it becomes -12 and 6-12 is -6 and not 6 so power of x should be -6 i.e x^-6 and not x^6

So, the correct answer is =\frac{27}{4x^{6}y^{8}}

Keywords: Exponents

Learn more about Exponents at:

  • brainly.com/question/13174254
  • brainly.com/question/13174255
  • brainly.com/question/13174259

#learnwithBrainly

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3 years ago
Which number replaces the box to make this number sentence true?
Nat2105 [25]
8\cdot(4+7)=32+56=88
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3 years ago
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