It may seem remarkable that we can learn about the composition of distant stars by studying the light they emit. In fact, we can learn a great deal, not only about the chemical elements present, but also about physical conditions. The key is to spread the light out by color, producing a spectrum like the one shown in Fig. 1. This lab explores some of the basic ideas used to analyze spectra.
Answer: V2= 41.2mL
Explanation:
Givens:
* V1= 20ml
* T1 = -109 ⁰C --> K= ⁰C + 273.15 --> 164.15 K
* V2 = ??
* T2= 338.15 K
Use Charles law V1/T1 = V2/T2
Since we are looking for V2 we can rearrange the formula to
V2= (T2 x V1) /T1
V2= (338.15K x 20mL) / 164.15 K
V2= 41.2mL
NOTE:
Temperature should always be in K not in ⁰C or ⁰F
To convert from C to K use
*K= ⁰C + 273.15
Enter your C value in the ( ⁰C ) and you can get K
He answer is 4.9 the graph to the right really means nothing.
<span>Scientific notation is used to express large numbers in a way that is to use, readable, comparable to other numbers and convenient. It is especially useful for things that are very large and very small because it is very tedious to work with many zero's when completing complex math problems.</span>
Answer:
try c atom i hope this helps!! : )
Explanation: