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Sladkaya [172]
3 years ago
6

WILL MARK BRAINLIEST AND WILL GET 50 POINTS!! HURRY

Chemistry
1 answer:
yuradex [85]3 years ago
4 0

Answer:

Hi

Explanation:

2 or 4

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What are the primary atoms that make up the scents that we smell?
Scorpion4ik [409]

Answer:

Molecules make scents. Aromatic ones (That is, containing rings of carbon atoms with delocalised electrons). Some unpleasant smells are due to hydrogen and sulphur groups.

Explanation:

3 0
3 years ago
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Explain how to count the number of elements in a compound.
Anna35 [415]

Answer:

Simply identify what elements are in a compound

Explanation:

For example in NaCl we have sodium (Na) and Chlorine (Cl)

In order to do this you would need to recognise the symbols for a certain element: O for oxygen; N for nitrogen; H for hydrogen etc.

3 0
3 years ago
You have a substance and begin a set of experiments in which you break it down into other substances through chemical reactions.
a_sh-v [17]
They're elements. Elements are the simplest form of any substance that cannot be broken down by any chemical methods, including electrolysis or even heat. Examples include oxygen, hydrogen etc.
3 0
4 years ago
If you did not use a watch glass to cover your stock iodine solution, and the concentration of iodine decreased over the course
anygoal [31]

Answer::

<u><em>Lower rate of reaction</em></u>

Explanation:

Lower concentration of reactant in an experiment is indicative of fewer ions or atoms present, which means a slower rate of reaction. In a titration reaction for instance, the end point would take longer to be substantiated, thereby increasing volume of titres. This is further backed up by collision theory which states that more particles in a system improves combinations of molecules.

This however may not be the case if the iodine in question is  catalyst, in which case the change in concentration has no effect whatsoever on the reaction rte.

I hope this explanation fits the brief.

5 0
3 years ago
1. Calculate how many moles of glycine are in a 130.0-g sample of glycine.2. Calculate the percent nitrogen by mass in glycine.
Alexxx [7]

Answer:

n=1.732mol

\% N=18.7\%

Explanation:

Hello!

In this case, since the molecular formula of glycine is C₂H₅NO₂, we realize that the molar mass is 75.07 g/mol; thus, the moles in 130.0 g of glycine are:

n=130.0g*\frac{1mol}{75.07 g}\\\\ n=1.732mol

Furthermore, we can notice 75.07 grams of glycine contains 14.01 grams of nitrogen; thus, the percent nitrogen turns out:

\% N=\frac{14.01}{75.07}*100\% \\\\\% N=18.7\%

Best regards!

4 0
3 years ago
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